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Part C How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures. ? m= Submit Request Answer Provide Feedback

Part C How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures. ? m= Submit Request Answer Provide Feedback

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures. 

The fizz produced when an Alka-Seltzer® tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO3) and citric acid (H3C6H5O7):  3NaHCO3(aq)+H3C6H5O7(aq)→3CO2(g)+3H2O(l)+Na3C6H5O7(aq)3NaHCO3(aq)+H3C6H5O7(aq)→3CO2(g)+3H2O(l)+Na3C6H5O7(aq)

In a certain experiment, 1.40 gg of sodium bicarbonate and 1.40 gg of citric acid are allowed to react.

The fizz produced when an Alka-Seltzer® tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO3) and citric acid (H3CH;O7): Express your answer in grams to three significant figures. 3NAHCO3 (aq) +H3C,H5O7(aq) → 3CO2 (g) + 3H,O(1) + Na3C,H507(aq) m = 0.733 g In a certain experiment, 1.40 g of sodium bicarbonate and 1.40 g of citric acid are allowed to react. Submit Previous Answers v Correct Since NaHCO3 is the limiting reactant, the amount of available NaHCO3 determines the amount of CO2 produced amount of CO2 produced using the conversion factor derived from the stoichiometric ratio in the balanced chemical e with the number of moles of NaHCO3 calculated in Part A: 3 mol CO2 moles CO, = 1.67 × 10 ² mol NaHCO, x = 1.67 x 10 2 mol CO2 3 mol NaHCO, Convert the number of moles of CO2 to grams using the molar mass of CO2 as a conversion factor: 44.01 g CO2 grams CO2 = 1.67 × 10 ² mol CO, x = 0.733 g CO2 1 molCO2 Part C How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures. ? m = Submit Request Answer Provide Feedback
Transcribed Image Text:The fizz produced when an Alka-Seltzer® tablet is dissolved in water is due to the reaction between sodium bicarbonate (NaHCO3) and citric acid (H3CH;O7): Express your answer in grams to three significant figures. 3NAHCO3 (aq) +H3C,H5O7(aq) → 3CO2 (g) + 3H,O(1) + Na3C,H507(aq) m = 0.733 g In a certain experiment, 1.40 g of sodium bicarbonate and 1.40 g of citric acid are allowed to react. Submit Previous Answers v Correct Since NaHCO3 is the limiting reactant, the amount of available NaHCO3 determines the amount of CO2 produced amount of CO2 produced using the conversion factor derived from the stoichiometric ratio in the balanced chemical e with the number of moles of NaHCO3 calculated in Part A: 3 mol CO2 moles CO, = 1.67 × 10 ² mol NaHCO, x = 1.67 x 10 2 mol CO2 3 mol NaHCO, Convert the number of moles of CO2 to grams using the molar mass of CO2 as a conversion factor: 44.01 g CO2 grams CO2 = 1.67 × 10 ² mol CO, x = 0.733 g CO2 1 molCO2 Part C How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures. ? m = Submit Request Answer Provide Feedback
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