Part (c) Given the coordinate system specified in the problem statement, write an expression for the sum of the forces in the y-direction. Part (d) Write an expression to show the relationship between the maximum friction force, Ff, and the normal force, F. Part (e) Calculate the magnitude of F, in Newtons, if F is at its maximum.

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(b) Write an expression for the sum of the forces in the x-direction using the variables from the above Free Body Diagram.

ΣFx=

  • Part (c) Given the coordinate system specified in the problem statement, write an expression for the sum of the forces in the y-direction.
  • Part (d) Write an expression to show the relationship between the maximum friction force,
  • Ff, and the normal force, F.
  • Part (e) Calculate the magnitude of F, in Newtons, if F is at its maximum.
### Understanding Friction and Applied Force

**Problem Statement:**
A stone that has a mass of \( m = 4.5 \, \text{kg} \) rests on a horizontal plane. The coefficient of static friction, \( \mu_s \), is \( 0.25 \). A horizontal force, \( F \), is applied to the stone, and it is just big enough to get the stone to begin moving.

**Explanation:**

- **Mass of the Stone:** \( m = 4.5 \, \text{kg} \)
- **Coefficient of Static Friction:** \( \mu_s = 0.25 \)
- **Applied Force:** \( F \) (This is the force required to overcome the static friction and move the stone.)

#### Diagram Description:

The diagram shows a block (representing the stone) resting on a horizontal surface. The block has the mass symbol \( m \) written on it. 

- An arrow labeled \( F \) points to the right, indicating the direction of the applied horizontal force.
- Below the block, near the interface between the block and the plane, is the label \( \mu_s \), representing the coefficient of static friction.
- There is a two-dimensional coordinate system with \( x \)- and \( y \)-axes indicating the horizontal and vertical directions, respectively.

#### Concept of Static Friction:

Static friction \( f_s \) is the frictional force that resists the movement of two surfaces in contact. It must be overcome by an applied force for the object to begin moving.

Mathematically, static friction can be represented as:
\[ f_s \leq \mu_s \cdot N \]

Where:
- \( f_s \) is the static frictional force.
- \( \mu_s \) is the coefficient of static friction.
- \( N \) is the normal force (equal to the gravitational force on the object when on a horizontal surface).

Here, the normal force \( N \) is given by the weight of the stone:
\[ N = m \cdot g \]
\[ N = 4.5 \, \text{kg} \times 9.81 \, \text{m/s}^2 \]
\[ N \approx 44.145 \, \text{N} \]

The maximum static frictional force is:
\[ f_s^{\text{max}} = \mu_s
Transcribed Image Text:### Understanding Friction and Applied Force **Problem Statement:** A stone that has a mass of \( m = 4.5 \, \text{kg} \) rests on a horizontal plane. The coefficient of static friction, \( \mu_s \), is \( 0.25 \). A horizontal force, \( F \), is applied to the stone, and it is just big enough to get the stone to begin moving. **Explanation:** - **Mass of the Stone:** \( m = 4.5 \, \text{kg} \) - **Coefficient of Static Friction:** \( \mu_s = 0.25 \) - **Applied Force:** \( F \) (This is the force required to overcome the static friction and move the stone.) #### Diagram Description: The diagram shows a block (representing the stone) resting on a horizontal surface. The block has the mass symbol \( m \) written on it. - An arrow labeled \( F \) points to the right, indicating the direction of the applied horizontal force. - Below the block, near the interface between the block and the plane, is the label \( \mu_s \), representing the coefficient of static friction. - There is a two-dimensional coordinate system with \( x \)- and \( y \)-axes indicating the horizontal and vertical directions, respectively. #### Concept of Static Friction: Static friction \( f_s \) is the frictional force that resists the movement of two surfaces in contact. It must be overcome by an applied force for the object to begin moving. Mathematically, static friction can be represented as: \[ f_s \leq \mu_s \cdot N \] Where: - \( f_s \) is the static frictional force. - \( \mu_s \) is the coefficient of static friction. - \( N \) is the normal force (equal to the gravitational force on the object when on a horizontal surface). Here, the normal force \( N \) is given by the weight of the stone: \[ N = m \cdot g \] \[ N = 4.5 \, \text{kg} \times 9.81 \, \text{m/s}^2 \] \[ N \approx 44.145 \, \text{N} \] The maximum static frictional force is: \[ f_s^{\text{max}} = \mu_s
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