p lease just part b Part BNow find the magnitude of the magnetic field that will cause the charge to travel in a straight line under the combined actionof electric and magnetic fields. (Figure 2)Express the magnetic field Bbal that will just balance the applied electric field in terms of some or all of the variables9, v, and E.► View Available Hint(s)IVE ΑΣΦ?Bbal =Submit When a particle with charge q moves across amagnetic field of magnitude B, it experiences a forceto the side. If the proper electric field É issimultaneously applied, the electric force on thecharge will be in such a direction as to cancel themagnetic force with the result that the particle willtravel in a straight line. The balancing conditionprovides a relationship involving the velocity of theparticle. In this problem you will figure out how toarrange the fields to create this balance and thendetermine this relationship.Figure1 of 2V = 0IonsoutV = |E||dIonsourceLslitPart AConsider the arrangement of ion source and electric field plates shown in the figure. (Figure 1)The ion source sends particleswith velocity along the positive x axis. They encounter electric field plates spaced a distance d apart that generate auniform electric field of magnitude E in the +y direction. To cancel the resulting electric force with a magnetic force, amagnetic field (not shown) must be added in which direction? Using the right-hand rule, you can see that the positive z axis isdirected out of the screen.Choose the direction of B.► View Available Hint(s)î–îĴОOkSubmit Previous AnswersCorrect

Answered: Image /qna-images/answer/239e37bb-728d-48b1-8945-d9aa24decdc6.jpg

Answered: Part B Now find the magnitude of the…

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