Part B: Mass swinging in a horizontal circleCalculate 0 given the masses of the swinging and hanging objects (provided in second video).Compare this value to an image from the third video. Does it seem reasonable?TheoryHere is a side view of the experiment, showing the forces acting on the swinging mass. Note thatbecause the hanging mass stays in equilibrium, T = mµg.4. The third video includes 40 revolutions of the swinging mass for three different values of L: 50,75, and 100 cm. Note that these three values were referred to as "radii" in the video, but strictlyspeaking they are L, not r. We could approximater with L as they are close to one another, butsince we have the angle 0, we might as well do a bit of trigonometry and calculate the actual radii.m=mass of swinging massmu = mass of hanging massL= length of string from top of tube to swinging massr=radius of circular motionComplete the following table. Use the third video to measure the times for 40 revolutions.Time for 40revolutions (s)v² (m²/s*)Side ViewL (m)r (m)Period (s)v (m/s)0.500Tension T0.7501.000Weight WPlotting the Data5. Use whatever software you choose to plot speed squared vs radius, and find the best-fit line tothe data. Paste the graph below (it should include the individual data points and the best-fit line)and write down the equation for your best-fit line.1. Write down Newton's Second Law for the swinging mass in the radial and vertical directions,including the expression for centripetal acceleration.Radial direction:Comparing Data and Theory6. Compare the value of the slope for the line above to the value for the slope given by the formulafor the proportionality constant C from number 2. Calculate the percent relative error betweenthese values.Vertical direction:2. By using the equations above, find the relationship between speed and radius. You should findthat v? is proportional to r, that is v2 = Cr, where C is a proportionality constant. Using the factthat T2 = T? + T2, write C as a function of the two masses and the gravitational acceleration g.Data and Calculations3. Note that for any value of L, 0 is the same sinceTzsin 0 =Tmgm

(1) Given: The diagram is as follows: Introduction: The second law states that the acceleration of…

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