Part B For 470.0 mL of a buffer solution that is 0.160 M in HC2H3O2 and 0.120 M in NaC₂ H3 O2, calculate the initial pH and the final pH after adding 1.9x10-2 mol of HCI. ( Ka (HC2H3O2) = 1.8 x 10-5.) Express your answers using two decimal places separated by a comma. pHinitial, PHfinal = Submit Request Answer Part C 15| ΑΣΦ pHinitial, PHfinal = For 470.0 mL of a buffer solution that is 0.145 M in CH3 CH₂NH₂ and 9.00x10-2 M in CH3 CH₂NH3 Cl, calculate the initial pH and the final pH after adding 1.9x10-2 mol of HCl. ( K(CH,CH,NH,) = 5.6 × 10 *.) Express your answers using two decimal places separated by a comma. IVE ΑΣΦ ? Submit Request Answer ?
Part B For 470.0 mL of a buffer solution that is 0.160 M in HC2H3O2 and 0.120 M in NaC₂ H3 O2, calculate the initial pH and the final pH after adding 1.9x10-2 mol of HCI. ( Ka (HC2H3O2) = 1.8 x 10-5.) Express your answers using two decimal places separated by a comma. pHinitial, PHfinal = Submit Request Answer Part C 15| ΑΣΦ pHinitial, PHfinal = For 470.0 mL of a buffer solution that is 0.145 M in CH3 CH₂NH₂ and 9.00x10-2 M in CH3 CH₂NH3 Cl, calculate the initial pH and the final pH after adding 1.9x10-2 mol of HCl. ( K(CH,CH,NH,) = 5.6 × 10 *.) Express your answers using two decimal places separated by a comma. IVE ΑΣΦ ? Submit Request Answer ?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Part B
For 470.0 mL of a buffer solution that is 0.160 M in HC2H3O2 and 0.120 M in NaC₂H3O2, calculate the initial pH and the final pH after adding 1.9x10-2 mol of HCI. (
Ka (HC₂H3O2) = 1.8 x 10-5.)
Express your answers using two decimal places separated by a comma.
pHinitial pHfinal =
Submit Request Answer
Part C
15| ΑΣΦ
pHinitial, pHfinal =
For 470.0 mL of a buffer solution that is 0.145 M in CH3 CH₂NH₂ and 9.00x10-2 M in CH3 CH₂NH3 Cl, calculate the initial pH and the final pH after adding 1.9x10-2 mol of HCl. (
Kb (CH3CH₂NH₂) = 5.6 x 10-4.)
Express your answers using two decimal places separated by a comma.
IVE| ΑΣΦ
?
Submit Request Answer
?
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