The rays of the Sun that cause tanning and burningare in the ultraviolet portion of the electromagneticspectrum. These rays are categorized bywavelength: So-called UV-A radiation haswavelengths in the range of 320-380 nm, whereasUV-B radiation has wavelengths in the range of290-320 nm.Part BCalculate the energy of a mole of 330 nm photons.17 ΑΣΦE= 10Submit45fTPrevious Answers Request Answer?X Incorrect; Try Again; 2 attempts remainingkJ/mol

To solve this problem we have to calculate the energy of one mole of photons. Given that Wavelength ((λ) = 330 nm = 330 × 10-9 m Plank constant (h) = 6.626 × 10-34 Js Speed of light (c) = 3 ×108 m/s 1 mole of photons = 6.022 × 1023 photons Since we know thatEnergy of one photon will be calculated as E = hc/ (λ) ={( 6.626 × 10-34 Js ) × (3 ×108 m/s) }/ (330 × 10-9 m ) = 6.02 × 10-19 J Now, Energy of one photon= 6.02 × 10-19 J So, Energy of one mole of photons = 6.022 × 1023 /mol × 6.02 × 10-19 J = 3.6 × 105 J/mol Energy of photons in kilojoules will be given as 3.6 × 105 × 10-3 kJ/mol = 360 kJ Answer: 360 kJ

Answered: Part B Calculate the energy of a mole…

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Chemistry

Part B Calculate the energy of a mole of 330 - nm photons. E = 10 45 ΑΣΦ ? S kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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