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Part A You decide to use your body as a Camot heat engine. The operating gas is in a tube with one end In your mouth (where the temperature is 37.0 "C) and the other end at the surface of your skin, at 30.0 °C. What is the maximum efficiency of such a heat engine? Would it be a very useful engine? e = 2.26 % Previous Answers v Correct Part B Suppose you want to use this human engine to lift a 2.45 kg box from the floor to a tabletop 1.30 m above the floor. How much must you increase the gravitational potential energy? V = 31.2 J Submit Previous Answers

Part A You decide to use your body as a Camot heat engine. The operating gas is in a tube with one end In your mouth (where the temperature is 37.0 "C) and the other end at the surface of your skin, at 30.0 °C. What is the maximum efficiency of such a heat engine? Would it be a very useful engine? e = 2.26 % Previous Answers v Correct Part B Suppose you want to use this human engine to lift a 2.45 kg box from the floor to a tabletop 1.30 m above the floor. How much must you increase the gravitational potential energy? V = 31.2 J Submit Previous Answers

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Solve for part D!!! Thank you!
Part C Suppose you want to use this human engine to lift a 2.45 kg box from the floor to a tabletop 1.30 m above the floor. How much heat input is needed to accomplish this? Q = 1380 J Submit Previous Answers v Correct Part D How many 350 calorie (those are food calories, remember) candy bars must you eat to lift the box in this way? Recall that 80.0 % of the food energy goes into heat. ΗΥ ΑΣ φ, ? candy bars
Transcribed Image Text:Part C Suppose you want to use this human engine to lift a 2.45 kg box from the floor to a tabletop 1.30 m above the floor. How much heat input is needed to accomplish this? Q = 1380 J Submit Previous Answers v Correct Part D How many 350 calorie (those are food calories, remember) candy bars must you eat to lift the box in this way? Recall that 80.0 % of the food energy goes into heat. ΗΥ ΑΣ φ, ? candy bars
Part A You decide to use your body as a Camot heat engine. The operating gas is in a tube with one end In your mouth (where the temperature is 37.0 "C) and the other end at the surface of your skin, at 30 0 °C What is the maximum efficiency of such a heat engine? Would it be a very useful engine? e = 2.26 % Previous Answers v Correct Part B Suppose you want to use this human engine to lift a 2.45 kg box from the floor to a tabletop 1.30 m above the floor. How much must you increase the gravitational potential energy? V = 31.2 J Submit Previous Answers
Transcribed Image Text:Part A You decide to use your body as a Camot heat engine. The operating gas is in a tube with one end In your mouth (where the temperature is 37.0 "C) and the other end at the surface of your skin, at 30 0 °C What is the maximum efficiency of such a heat engine? Would it be a very useful engine? e = 2.26 % Previous Answers v Correct Part B Suppose you want to use this human engine to lift a 2.45 kg box from the floor to a tabletop 1.30 m above the floor. How much must you increase the gravitational potential energy? V = 31.2 J Submit Previous Answers
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