**Problem 20.67****Part A**What is the effect on the emf of the cell shown in the figure below, which has the overall reaction \( \text{Zn}(s) + 2\text{H}^+(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{H}_2(g) \), for each of the following changes?![Electrochemical cell diagram]- **Diagram Explanation:** - The diagram depicts an electrochemical cell with a Zn anode and a cathode half-cell containing a standard hydrogen electrode (SHE). - The anode half-cell has \( \text{NO}_3^- \) ions, \( \text{Zn}^{2+} \) ions, and a Zn electrode. - The cathode half-cell contains H₂ gas and has a SHE with \( \text{NO}_3^- \) and \( \text{Na}^+ \) ions. - A voltmeter measures the emf between the two half-cells, displaying 0.76 V.**Sentence Completion:**Match the words in the left column to the appropriate blanks in the sentences on the right.- **Options:** - increases - decreases - does not change1. The pressure of the \( \text{H}_2 \) gas is increased in the cathode half-cell. As a result, Q: ______ ; consequently emf ______ . 2. Zinc nitrate is added to the anode half-cell. As a result, Q: ______ ; consequently emf ______ .3. Sodium hydroxide is added to the cathode half-cell, decreasing \([\text{H}^+]\). As a result, Q: ______ ; consequently emf ______ .4. The surface area of the anode is doubled. During this change, Q: ______ ; emf ______ .

Answered: Image /qna-images/answer/7c2f2e8a-ebb9-4781-82e4-727fed6ec49a.jpg

Part A What is the effect on the emf of the cell shown in figure below, which has the overall reaction Zn(s) + 2H+ (aq) → Zn²+ (aq) + H₂(g). for each of the following changes? 0.76 V Voltmeter. Zn anode Anode half-cell - NO Zn²+ NO- Zn(s)→→→→→→ Zn²+ (aq) + 2 e Match the words in the left column increases NO₂ decreases does not change Nat- NO₂ H+ 40 -H₂(g) Cathode half-cell (standard hydrogen electrode, SHE) 2 H+ (aq) + 2e H₂(g) to the appropriate blanks in the sentences on the right. The pressure of the H₂ gas is increased in the cathode half-cell. As a result. Q consequently emf Zinc nitrate is added to the anode half-cell. As a result, Q Sodium hydroxide is added to the cathode half-cell, decreasing [H]. As a result, Q consequently emf The surface area of the anode doubled. During this change. Q , consequently emf Reset Help emf 1

Part A What is the effect on the emf of the cell shown in figure below, which has the overall reaction Zn(s) + 2H+ (aq) → Zn²+ (aq) + H₂(g). for each of the following changes? 0.76 V Voltmeter. Zn anode Anode half-cell - NO Zn²+ NO- Zn(s)→→→→→→ Zn²+ (aq) + 2 e Match the words in the left column increases NO₂ decreases does not change Nat- NO₂ H+ 40 -H₂(g) Cathode half-cell (standard hydrogen electrode, SHE) 2 H+ (aq) + 2e H₂(g) to the appropriate blanks in the sentences on the right. The pressure of the H₂ gas is increased in the cathode half-cell. As a result. Q consequently emf Zinc nitrate is added to the anode half-cell. As a result, Q Sodium hydroxide is added to the cathode half-cell, decreasing [H]. As a result, Q consequently emf The surface area of the anode doubled. During this change. Q , consequently emf Reset Help emf 1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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