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Part A Use the AH°F and AH°rxn information provided to calculate AH°† for IF: AH°f (kJ/mol) IF7(g) + I2(g) → IF5(g) + 2 IF(g) AH°rxn = -89 kJ %3D IF7(g) -941 IF5(g) -840 O -190 kJ/mol O 101 kJ/mol O 24 kJ/mol -146 kJ/mol -95 kJ/mol Submit Request Answer

Part A Use the AH°F and AH°rxn information provided to calculate AH°† for IF: AH°f (kJ/mol) IF7(g) + I2(g) → IF5(g) + 2 IF(g) AH°rxn = -89 kJ %3D IF7(g) -941 IF5(g) -840 O -190 kJ/mol O 101 kJ/mol O 24 kJ/mol -146 kJ/mol -95 kJ/mol Submit Request Answer

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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## Part A Use the \( \Delta H_f^\circ \) and \( \Delta H_{rxn}^\circ \) information provided to calculate \( \Delta H_f^\circ \) for IF: ### Given Data - **Reaction:** \( \text{IF}_7(g) + \text{I}_2(g) \rightarrow \text{IF}_5(g) + 2 \ \text{IF}(g) \) - **Reaction Enthalpy:** \( \Delta H_{rxn}^\circ = -89 \ \text{kJ} \) | Compound | \( \Delta H_f^\circ \) (kJ/mol) | |----------|----------------------------------| | IF\(_7\)(g) | -941 | | IF\(_5\)(g) | -840 | ### Options for \( \Delta H_f^\circ \) of IF(g): - \(-190\) kJ/mol - \(101\) kJ/mol - \(24\) kJ/mol - \(-146\) kJ/mol - \(-95\) kJ/mol [Submit] [Request Answer]
Transcribed Image Text:## Part A Use the \( \Delta H_f^\circ \) and \( \Delta H_{rxn}^\circ \) information provided to calculate \( \Delta H_f^\circ \) for IF: ### Given Data - **Reaction:** \( \text{IF}_7(g) + \text{I}_2(g) \rightarrow \text{IF}_5(g) + 2 \ \text{IF}(g) \) - **Reaction Enthalpy:** \( \Delta H_{rxn}^\circ = -89 \ \text{kJ} \) | Compound | \( \Delta H_f^\circ \) (kJ/mol) | |----------|----------------------------------| | IF\(_7\)(g) | -941 | | IF\(_5\)(g) | -840 | ### Options for \( \Delta H_f^\circ \) of IF(g): - \(-190\) kJ/mol - \(101\) kJ/mol - \(24\) kJ/mol - \(-146\) kJ/mol - \(-95\) kJ/mol [Submit] [Request Answer]
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