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Part A Use data given below to calculate AS° for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25 C Substance A,S, JK-1 mol 4 NO2 (9) + 2 H0 (1) + 02(9) → 4 HNO3 (ag) Cr (s) 23.8 Express your answer using one decimal place. CrzO3(s) 81.2 A,S° = -721.6 JK-' mol-1 CO (g) 197.7 CO2 (9) 213.8 Previous Answers Submit H2 (g) 130.7 H20 (9) v Correct 188.8 H20 (1) HNO, (ag) 70.0 146.0 Part B N2 (9) N204 (9) NO (9) NO, (9) 02 (9) KCIO, (s) 191.6 304.4 Try to rationalize the sign of A,S. 210.8 The answer is negative, which is consistent with a decrease in the number of moles of gas. 240.1 205.2 The answer is negative, which is consistent with an ionic compound HNO; formed in the reaction. 143.1 The answer is negative, which is consistent with a decrease in the number of moles of gas. KC10, (s) 151.0 O The answer is negative, which is consistent with an increase in the number of moles of liquid components. Request Answer Submit • Part C CrOs(s) +3 CO (9) →2 Cr (s) + 3 CO2 (9) Express your answer using one decimal place. 4,S° - 14.7 JK-' mol Submit Previous Answers v Correct Part D Try to rationalize the sign of A, S". O The change is small and positive because the number of moles of compounds increases. O The change is small because the number of moles of gas is constant. O The change is small because Cr2O3 is more active then metalic Cr. Submit Request Answer

Part A Use data given below to calculate AS° for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25 C Substance A,S, JK-1 mol 4 NO2 (9) + 2 H0 (1) + 02(9) → 4 HNO3 (ag) Cr (s) 23.8 Express your answer using one decimal place. CrzO3(s) 81.2 A,S° = -721.6 JK-' mol-1 CO (g) 197.7 CO2 (9) 213.8 Previous Answers Submit H2 (g) 130.7 H20 (9) v Correct 188.8 H20 (1) HNO, (ag) 70.0 146.0 Part B N2 (9) N204 (9) NO (9) NO, (9) 02 (9) KCIO, (s) 191.6 304.4 Try to rationalize the sign of A,S. 210.8 The answer is negative, which is consistent with a decrease in the number of moles of gas. 240.1 205.2 The answer is negative, which is consistent with an ionic compound HNO; formed in the reaction. 143.1 The answer is negative, which is consistent with a decrease in the number of moles of gas. KC10, (s) 151.0 O The answer is negative, which is consistent with an increase in the number of moles of liquid components. Request Answer Submit • Part C CrOs(s) +3 CO (9) →2 Cr (s) + 3 CO2 (9) Express your answer using one decimal place. 4,S° - 14.7 JK-' mol Submit Previous Answers v Correct Part D Try to rationalize the sign of A, S". O The change is small and positive because the number of moles of compounds increases. O The change is small because the number of moles of gas is constant. O The change is small because Cr2O3 is more active then metalic Cr. Submit Request Answer

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please help me with part b,d,f,h as they are all part of one question. I really want to make sure i get them right. I will highly consider giving thumbs up 

Part A Use data given below to calculate A,S° for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25° C Substance A,S, JK-1 mol- 4 NO2 (g) + 2 H20 (1) + 02(9) →4 HNO3 (ag) Cr (s) 23.8 Express your answer using one decimal place. Cr2O3(s) 81.2 A,S° - -721.6 JK-' mol- CO (g) 197.7 CO2 (g) 213.8 Previous Answers Submit H2 (9) H20 (g) H20 (1) 130.7 188.8 v Correct 70.0 HNO: (aq) 146.0 • Part B N2 (9) N20, (g) 191.6 304.4 Try to rationalize the sign of A, S°. NO (9) NO2 (9) O, (9) 210.8 The answer is negative, which is consistent with a decrease in the number of moles of gas. 240.1 205.2 O The answer is negative, which is consistent with an ionic compound HNO3 formed in the reaction. KCIO, (s) 143.1 The answer is negative, which is consistent with a decrease in the number of moles of gas. KCIO, (8) 151.0 The answer is negative, which is consistent with an increase in the number of moles of liquid components. Submit Request Answer Part C Cr2O3(s) + 3 CO (9) → 2 Cr (s) + 3 CO2 (9) Express your answer using one decimal place. A,S- 14.7 JK- mol-1 Submit Previous Answers v Correct Part D Try to rationalize the sign of A, S°. O The change is small and positive because the number of moles of compounds increases. The change is small because the number of moles of gas is constant. The change is small because Cr2Og is more active then metalic Cr. Submit Request Answer
Transcribed Image Text:Part A Use data given below to calculate A,S° for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25° C Substance A,S, JK-1 mol- 4 NO2 (g) + 2 H20 (1) + 02(9) →4 HNO3 (ag) Cr (s) 23.8 Express your answer using one decimal place. Cr2O3(s) 81.2 A,S° - -721.6 JK-' mol- CO (g) 197.7 CO2 (g) 213.8 Previous Answers Submit H2 (9) H20 (g) H20 (1) 130.7 188.8 v Correct 70.0 HNO: (aq) 146.0 • Part B N2 (9) N20, (g) 191.6 304.4 Try to rationalize the sign of A, S°. NO (9) NO2 (9) O, (9) 210.8 The answer is negative, which is consistent with a decrease in the number of moles of gas. 240.1 205.2 O The answer is negative, which is consistent with an ionic compound HNO3 formed in the reaction. KCIO, (s) 143.1 The answer is negative, which is consistent with a decrease in the number of moles of gas. KCIO, (8) 151.0 The answer is negative, which is consistent with an increase in the number of moles of liquid components. Submit Request Answer Part C Cr2O3(s) + 3 CO (9) → 2 Cr (s) + 3 CO2 (9) Express your answer using one decimal place. A,S- 14.7 JK- mol-1 Submit Previous Answers v Correct Part D Try to rationalize the sign of A, S°. O The change is small and positive because the number of moles of compounds increases. The change is small because the number of moles of gas is constant. The change is small because Cr2Og is more active then metalic Cr. Submit Request Answer
Part E KC103 (s) + 02 (9) → KCI04 (s) Express your answer using one decimal place. A,S° = -94.7 JK-1 mol-! Submit Previous Answers Correct Part F Try to rationalize the sign of A, S°. O The answer is negative, which is consistent with a higher activity of O2. O The answer is negative, which is consistent with loser activity of KC1O4 (s). O The answer negative, which is consistent with a decrease in the number of moles of gas. Submit Request Answer Part G N204 (g) + 4 H2 (g) → N2 (9) + 4 H2O (g) Express your answer using one decimal place. A,S° = 119.6 JK-' mol-! Submit Previous Answers v Correct Part H Try to rationalize the sign of A,S°. O The answer positive, which is consistent with water production that will soon become a liquid. O The answer is positive, which is consistent with higher atomic weight of nitrogen in comparison with hydrogen and its higher mobility. O The answer is positive, which is consistent with 1 mole of a complex gas and 4 moles of a simple gas going to 1 mole of simple gas and 4 moles of a complex gas. Submit Request Answer
Transcribed Image Text:Part E KC103 (s) + 02 (9) → KCI04 (s) Express your answer using one decimal place. A,S° = -94.7 JK-1 mol-! Submit Previous Answers Correct Part F Try to rationalize the sign of A, S°. O The answer is negative, which is consistent with a higher activity of O2. O The answer is negative, which is consistent with loser activity of KC1O4 (s). O The answer negative, which is consistent with a decrease in the number of moles of gas. Submit Request Answer Part G N204 (g) + 4 H2 (g) → N2 (9) + 4 H2O (g) Express your answer using one decimal place. A,S° = 119.6 JK-' mol-! Submit Previous Answers v Correct Part H Try to rationalize the sign of A,S°. O The answer positive, which is consistent with water production that will soon become a liquid. O The answer is positive, which is consistent with higher atomic weight of nitrogen in comparison with hydrogen and its higher mobility. O The answer is positive, which is consistent with 1 mole of a complex gas and 4 moles of a simple gas going to 1 mole of simple gas and 4 moles of a complex gas. Submit Request Answer
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