Part a to c Please  A budding electronics hobbyist wants to make a simple 1.5 nF capacitor for tuning her crystal radio, using two sheets of aluminum foil as plates, with a few sheets of paper between them as a dielectric. The paper has a dielectric constant of 5.0, and the thickness of one sheet of it is 0.16 mm . Part A If the sheets of paper measure 25 cm × 36 cm and she cuts the aluminum foil to the same dimensions, how many sheets of paper should she use between her plates to get the proper capacitance?  Part B Suppose for convenience she wants to use a single sheet of posterboard, with the same dielectric constant but a thickness of 15.0 mm , instead of the paper. What area of aluminum foil will she need for her plates to get her 1.5 nF of capacitance?  Part C Suppose she goes high-tech and finds a sheet of Teflon of the same thickness as the posterboard to use as a dielectric. Will she need a larger or smaller area of Teflon than of posterboard?

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Chapter1: Units, Trigonometry. And Vectors
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Part a to c Please 

A budding electronics hobbyist wants to make a simple 1.5 nF capacitor for tuning her crystal radio, using two sheets of aluminum foil as plates, with a few sheets of paper between them as a dielectric. The paper has a dielectric constant of 5.0, and the thickness of one sheet of it is 0.16 mm .

Part A If the sheets of paper measure 25 cm × 36 cm and she cuts the aluminum foil to the same dimensions, how many sheets of paper should she use between her plates to get the proper capacitance? 

Part B Suppose for convenience she wants to use a single sheet of posterboard, with the same dielectric constant but a thickness of 15.0 mm , instead of the paper. What area of aluminum foil will she need for her plates to get her 1.5 nF of capacitance? 

Part C Suppose she goes high-tech and finds a sheet of Teflon of the same thickness as the posterboard to use as a dielectric. Will she need a larger or smaller area of Teflon than of posterboard? 

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