A parallel-plate capacitor is to be constructed by using, as a dielectric, rubber with a dielectric constant of 3.20 and a dielectric strength of 25.0 MV/m. The capacitor is to have a capacitance of 1.60 nF and must be able to withstand a maximum potential difference of 4.00 kV. Part A What is the minimum area the plates of this capacitor can have? Express your answer in meters squared. A = Submit — ΑΣΦ Request Answer m²

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Chapter1: Units, Trigonometry. And Vectors
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A parallel-plate capacitor is to be constructed by using, as a dielectric, rubber with a dielectric constant
of 3.20 and a dielectric strength of 25.0 MV/m. The capacitor is to have a capacitance of 1.60 nF
and must be able to withstand a maximum potential difference of 4.00 kV.
Part A
What is the minimum area the plates of this capacitor can have?
Express your answer in meters squared.
A =
Submit
ΑΣΦ
Request Answer
w ?
m²
Transcribed Image Text:A parallel-plate capacitor is to be constructed by using, as a dielectric, rubber with a dielectric constant of 3.20 and a dielectric strength of 25.0 MV/m. The capacitor is to have a capacitance of 1.60 nF and must be able to withstand a maximum potential difference of 4.00 kV. Part A What is the minimum area the plates of this capacitor can have? Express your answer in meters squared. A = Submit ΑΣΦ Request Answer w ? m²
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