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Part a through b please  Part a)  In the following alum synthesis reaction 1.50 grams of aluminum are reacted with excess base and acid. 2 Al + 2 KOH + 4 H2SO4 + 22 H2O → 3 H2 + 2 KAl(SO4)2·12H2O  If 7.3 g of alum (molar mass = 474.41 g/mol) were collected from the above reaction, what is the percent yield of the reaction? a) 96. % b) 54. % c) 28. % d) 21. % Part b) The precipitate that would form when aqueous solutions of sodium sulfate and barium nitrate are mixed is, a) BaSO4 b) NaNO3 c) both BaSO4 and NaNO3 d) no precipitate forms

Part a through b please  Part a)  In the following alum synthesis reaction 1.50 grams of aluminum are reacted with excess base and acid. 2 Al + 2 KOH + 4 H2SO4 + 22 H2O → 3 H2 + 2 KAl(SO4)2·12H2O  If 7.3 g of alum (molar mass = 474.41 g/mol) were collected from the above reaction, what is the percent yield of the reaction? a) 96. % b) 54. % c) 28. % d) 21. % Part b) The precipitate that would form when aqueous solutions of sodium sulfate and barium nitrate are mixed is, a) BaSO4 b) NaNO3 c) both BaSO4 and NaNO3 d) no precipitate forms

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter3: Equation, The Mole, And Chemical Formulas
Section: Chapter Questions
Problem 3.133QE
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Part a through b please 

Part a)  In the following alum synthesis reaction 1.50 grams of aluminum are reacted with excess base and acid.

2 Al + 2 KOH + 4 H2SO4 + 22 H2O → 3 H2 + 2 KAl(SO4)2·12H2O

 If 7.3 g of alum (molar mass = 474.41 g/mol) were collected from the above reaction, what is the percent yield of the reaction?

a) 96. %

b) 54. %

c) 28. %

d) 21. %

Part b) The precipitate that would form when aqueous solutions of sodium sulfate and barium nitrate are mixed is,

a) BaSO4

b) NaNO3

c) both BaSO4 and NaNO3

d) no precipitate forms

 

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