Part A The width of an extra large rectangular poster is 8 inches more than half its length. The area of this poster is 306 square inches. Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster. In the box below, clearly indicate the necessary steps, including appropriate formula substitutions, diagrams, graphs, charts, etc. Utilize the information provided for the question to determine your answer. Click the box below to type your math work and answer. On the right side of the box, click the - button to start a new line. ) Part B Solve this equation algebraically to determine the dimensions of this poster, in inches. In the box below, clearly indicate the necessary steps, including appropriate formula substitutions, diagrams, graphs, charts, etc. Utilize the information provided for the question to determine your answer,
Unitary Method
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Speed, Time, and Distance
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
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