Homework Help is Here – Start Your Trial Now!
Science
Physics
• Part A The parallel axis theorem relates I the moment of inertia of an object about an axis passing through its center of mass, to I the moment of inertia of the same object about a parallel axis passing through point p. The mathematical statement of the theorem is I, = Im + Md, where dis the perpendicular distance from the center of mass to the axis that passes through point p, and M is the mass of the object. Suppose a uniform slender rod has length L and mass m. The moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by Im = mL?. Find Ind- the moment of inertia of the rod with respect to a parallel axis through one end of the rod. Express Ind in terms of m and L. Use fractions rather than decimal numbers in your answer. > View Available Hint(s) Lad" (m) (L²) Submit Previous Answers v Correct • Part B Now consider a cube of mass m with edges of length a. The moment of inertia Ilem of the cube about an axis through its center of mass and perpendicular to one of its faces is given by Iem = ma?. (Eigure 1)Find Inder. the moment of inertia about an axis p through one of the edges of the cube Express Ide in terms of m and a. Use fractions rather than decimal numbers in your answer. Figure 1 of 1> > View Available Hint(s)

• Part A The parallel axis theorem relates I the moment of inertia of an object about an axis passing through its center of mass, to I the moment of inertia of the same object about a parallel axis passing through point p. The mathematical statement of the theorem is I, = Im + Md, where dis the perpendicular distance from the center of mass to the axis that passes through point p, and M is the mass of the object. Suppose a uniform slender rod has length L and mass m. The moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by Im = mL?. Find Ind- the moment of inertia of the rod with respect to a parallel axis through one end of the rod. Express Ind in terms of m and L. Use fractions rather than decimal numbers in your answer. > View Available Hint(s) Lad" (m) (L²) Submit Previous Answers v Correct • Part B Now consider a cube of mass m with edges of length a. The moment of inertia Ilem of the cube about an axis through its center of mass and perpendicular to one of its faces is given by Iem = ma?. (Eigure 1)Find Inder. the moment of inertia about an axis p through one of the edges of the cube Express Ide in terms of m and a. Use fractions rather than decimal numbers in your answer. Figure 1 of 1> > View Available Hint(s)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
See similar textbooks
icon
Related questions
Question
Item 8 8 of 26 II Review | Constants Part A The parallel axis theorem relates Im, the moment of inertia of an object about an axis passing through its center of mass, to Ip, the moment of inertia of the same object about a parallel axis passing through point p. The mathematical statement of the theorem is I, = Iem + Md², where d is the perpendicular distance from the center of mass to the axis that passes through point p, and M is the mass of the object. Suppose a uniform slender rod has length L and mass m. The moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by Iem = mL. Find Iend, the moment of inertia of the rod with respect to a parallel axis through one end of the rod. Express Iend in terms of m and L. Use fractions rather than decimal numbers in your answer. • View Available Hint(s) {(m) (L²) Iend = Submit Previous Answers v Correct Part B Now consider a cube of mass m with edges of length a. The moment of inertia Iem of the cube about an axis through its center of mass and perpendicular to one of its faces is given by Iem = ma?. (Figure 1)Find Iedge, the moment of inertia about an axis p through one of the edges of the cube Express Indre in terms of m and a. Use fractions rather than decimal numbers in your answer. Figure 1 of 1 > • View Available Hint(s) "ν ΑΣφ Iedge = Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining р-аxis
Transcribed Image Text:Item 8 8 of 26 II Review | Constants Part A The parallel axis theorem relates Im, the moment of inertia of an object about an axis passing through its center of mass, to Ip, the moment of inertia of the same object about a parallel axis passing through point p. The mathematical statement of the theorem is I, = Iem + Md², where d is the perpendicular distance from the center of mass to the axis that passes through point p, and M is the mass of the object. Suppose a uniform slender rod has length L and mass m. The moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by Iem = mL. Find Iend, the moment of inertia of the rod with respect to a parallel axis through one end of the rod. Express Iend in terms of m and L. Use fractions rather than decimal numbers in your answer. • View Available Hint(s) {(m) (L²) Iend = Submit Previous Answers v Correct Part B Now consider a cube of mass m with edges of length a. The moment of inertia Iem of the cube about an axis through its center of mass and perpendicular to one of its faces is given by Iem = ma?. (Figure 1)Find Iedge, the moment of inertia about an axis p through one of the edges of the cube Express Indre in terms of m and a. Use fractions rather than decimal numbers in your answer. Figure 1 of 1 > • View Available Hint(s) "ν ΑΣφ Iedge = Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining р-аxis
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Rotational Kinetic energy
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON
SEE MORE TEXTBOOKS