Part (a) Select an expression for the impulse I that the baseball experiences when it bounces off the concrete.I = m(/2gh, - /2gh,) I= m= m(/2gh, – /2gh,)I = /2gh2 + /2ghI = m/2gh2I = m(/2gh, + V2gh,)I = m/2gh, Problem 2: A baseball of mass m = 0.25 kg is dropped from a height h, = 2.05 m. It bounces from the concrete below and returns to a final height ofh2 = 1.35 m. Neglect air resistance.Randomized Variablesm = 0.25 kgh = 2.05 mh2 = 1.35 m

Answered: Image /qna-images/answer/e81c1ef9-6494-4773-9951-cf8d290520d7.jpg

Part (a) Select an expression for the impulse I that the baseball experiences when it bounces off the concrete. 1 = m(/2gh, - /2gh,) I = m(/2gh, – /2gh2) I = /2gh2 + /2gh, I = m/2gh2 I = m(/2gh2 +V2gh1) I = m/2gh1

Part (a) Select an expression for the impulse I that the baseball experiences when it bounces off the concrete. 1 = m(/2gh, - /2gh,) I = m(/2gh, – /2gh2) I = /2gh2 + /2gh, I = m/2gh2 I = m(/2gh2 +V2gh1) I = m/2gh1

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A 61.00 kg hockey play skates due North on a frictionless ice rink with a velocity of 10.00 He is tackled by a second hockey player of mass 78.00 kg who was initially skating due West at velocity 15.00 Assume the collision is perfectly inelastic, resulting in the two players "sticking together." m S W of Ꮎ N S E m S
4. In a perfectly inelastic collision, two objects collide and stick together. Is momentum conserved in the collision? Is energy conserved? Why or why not?
What angle does the Blue ball go off on after the collision? (measured off it's original direction (x-direction)) Estimate: In the current setup, how fast would the Blue ball need to be going initially to come off at an angle of 5 degrees?
If the momentum of an object is trippled, its kinetic energy will change by what factor? I think it changes 9 times? not sure.
The bumper of a car has a force sensor mounted inside which records the force vs time graph during crash testing. A particular collision occurs between t = 0.075s and t = 2.32s and can be modelled by the following function: F(t) = 4t4 – 80t² + 140t – 10 A graph of the collision is also provided below: Impulse 60 50 40 30 20 10 1 time (s) Part A The impulse during the collision will be while the maximum force experience by the bumper will be 75 kg · m/s, 33N 54 kg · m/s, 54N O 75 kg · m/s, 54N 54 kg · m/s, 33N (N) aɔ10
٩٩
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 6.) Ball 1 : m1 = 8 slugs and vi1 = 3 ft/s to the RIGHT Ball 2: m2 = 4 slugs and vi2 = 0 Ball 3: m3 = 6 slugs and vi3 = 0 picture the three balls all siting on a flat surface with some space between them. AFTER ball 1 strikes ball 2, ball 1 is traveling at 1.5 ft/s to the LEFT AFTER ball 2 strikes ball 3, ball 2 is traveling at 3 ft/s to the LEFT a,) What is the direction (left or right) and final velocity of ball 3? Vf3 =? Show all unit conversions step by step, if any.
m1: 1 kg m2: 2 kg V1i: 1 m/s V2i: -2 m/s Find the following values from the simulation V1f. -3.00 V2f. O Verify that momentum is conserved and kinetic energy is conserved by completing the following table: Momentum after Kinetic energy Momentum before collision Kinetic energy after collision collision before collision m1V1i + m2V2i m1Vif + m2V2f 2 mivir + ½ m2v21? 2 miV1 + ½ m2V2r
Determine the unknown velocity value. Assume that the collisions occur in an isolated system.
Two balls of mass m and M are attached by strings of length L. The two balls are initially at rest at an angle θ, and are then released. The balls undergo a totally inelastic collision at the bottom of their swings. Assume that m = 1.7kg, M = 2.8kg, L = 0.80m and θ = 67o.a) Calculate the speed of the balls immediately after the totally inelastic collision.b) To what maximum angle do the conjoined balls rise after the collision?
When there is motion is both directions, state which direction is positive at the START of the problem. For the impulse-momentum and the conservation of momentum problems: Plug your GIVEN VALUES into the equation FIRST then do the algebra. Use the following equations: F t = m vf -m vi m1 vi1 + m2 vi2 = m1 vf1 + m2 vf2 m1 vi1 + m2 vi2 = (m1 + m2) vf (m1 + m2) Vi = m1 vf1 + m2 vf2 2. ) The baseball is traveling at 90 mph to the left towards the batter. The batter strikes the 0.05 slug baseball with a force of 50.00 lbs. The bat is in contact with the softball for 0.25 seconds. Assume that the baseball is traveling directly in the opposite direction after being hit with the bat. a. what is the velocity of the baseball after being hit by the batter? show all unit conversions-if any, step by step.
A plasticine ball with a momentum of 4.0 kg•m/s [F] hits a wall and stops. What is the change in the ball's momentum? O 4.0 kg-m/s [B] 4.0 kg•m/s [F] 0.0 kg-m/s 8.0 kg-m/s [B] 8.0 kg-m/s [F]