A 61.00 kg hockey play skates due North on a frictionless ice rink with a velocity of 10.00. He is tackled by a second hockey player of mass 78.00 kg who was initially skating due West at velocity 15.00m. Assume the collision is perfectly inelastic, resulting in the two players "sticking together." W N - Ofe E
A 61.00 kg hockey play skates due North on a frictionless ice rink with a velocity of 10.00. He is tackled by a second hockey player of mass 78.00 kg who was initially skating due West at velocity 15.00m. Assume the collision is perfectly inelastic, resulting in the two players "sticking together." W N - Ofe E
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A 61.00 kg hockey player skates due North on a frictionless ice rink with a velocity of 10.00 m/s. He is tackled by a second hockey player of mass 78.00 kg who was initially skating due West at a velocity of 15.00 m/s. Assume the collision is perfectly inelastic, resulting in the two players "sticking together."
**Diagram Explanation:**
The diagram shows two hockey players on an ice rink:
- **First Hockey Player:** Moving Northward with an initial velocity represented by an upward arrow.
- **Second Hockey Player:** Moving Westward with an initial velocity represented by a leftward arrow.
The intersection of these two paths forms a right triangle with a hypotenuse representing the combined velocity vector after collision. The collision is at the origin of the coordinate system, where the vertical and horizontal axes intersect.
Key Variables:
- \( v_f \): Final velocity vector after collision.
- \( \theta \): Angle of the final velocity vector with respect to the horizontal axis (West-East line).
**Physics Concept:**
The problem involves a perfectly inelastic collision where momentum is conserved. The momentum components along the North and West directions can be resolved to find the resultant velocity and direction (\( v_f \) and \( \theta \)) of the combined mass after collision.

Transcribed Image Text:**Physics Problem: Hockey Collision**
**Question 1:**
What is the velocity (\( v_f \)) of the combined hockey players after the collision?
- ○ 9.49 \(\frac{m}{s}\)
- ○ 16.91 \(\frac{m}{s}\)
- ○ 25.37 \(\frac{m}{s}\)
- ○ 4.95 \(\frac{m}{s}\)
**Question 2:**
What angle from due North (\( \theta \)) do the hockey players move after the collision?
- ○ 40.45°
- ○ 62.46°
- ○ 49.55°
- ○ 27.54°
**Question 3:**
Is energy lost in the collision?
- ○ Yes
- ○ Cannot tell with information provided
- ○ No
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