Part AReplace the loading shown by an equivalent singleresultant force and specify the x and y coordinates of itsline of action. Assume F₁ = 100 N and F2 = 280 N. (Figure 1)Detrermine the resultant force.Enter the x, y and z components of the resultant force separated by commas.阿 ΑΣΦvecFR=SubmitRequest AnswerPart B?NDetermine the x and y coordinates of the its line of action.Express your answers using three significant figures separated by a comma.x, y =ΑΣΦvecSubmitRequest Answer?B F₁3 m3 m2m1 mFF22m 1m -3 m--y

Answered: Part A Replace the loading shown by an…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Consider a resultant force of 50N along the negative y-axis. The resultant was calculated as a sum of the following four tensile force: F1= 100N at 70, F2= 300N at 190 and F3 = 150N at 340 and F4 . Find the magnitude and the direction of the force F4. Find the force F4. Use the counter clockwise direction as the positive direction of the angle from the positive x-axis . Provide the answer to 2 decimal places.
Q1/ Determine the magnitude and direction of the resultant force in system :below P1 = 10 KN P2 = 35 KN 8 = 750 82 = 45° P3 = 50 KN
Part A Determine the moment of force F about point O. Express the result as a Cartesian vector. (Figure 1). Assume F = 510 N Enter the x, y and z components of the moment of force separated by commas. nν ΑΣφ ? vec Mo = Oi,0j, – 1.224k kN - m Submit Previous Answers Request Answer Figure 1 of 1 X Incorrect; Try Again; 3 attempts remaining Term 3: The correct answer does not depend on: k. Provide Feedback F 4 m 3 m
As shown in the image below, the rigid member ACB (with negligible thickness) is subjected to three forces. The forces are F1=340N, F2=360N, and F3=170N, an the angles Alpha=34 degrees and Beta=57 degrees. Replace these forces by a single resultant force, then determine the distance x(in m) where its line of action intersects segment AC, measured from point A. Answer must include 2 places after the decimal point.
Replace the force and couple moment system by an equivalent resultant force (Figure 1). Assume F₁ = 28 lb. ▼ Part A FR Y Part B Determine the magnitude of the equivalent resultant force Express your answer in pounds to three significant figures. 9= Submit Request Answer Submit Part C F₁ 3 ft y= 4 ft Submit Determine the direction of the equivalent resultant force. Express your answer in degrees to three significant figures. IVE| ΑΣΦ 11 vec 4 Ĉ VAX I vec Provide Feedback -5 ft F₂ = 10 lb Request Answer Specify its coordinate point of application (0, y) on the y axis Express your answer in feet to three significant figures. IVE ΑΣΦ 11 vec 3 Request Answer Ĉ O 25 B 2 ? y M₂ 100 lb ft 0 -3 ft- M₁ M, 170 lb ft ft lb F₁ - 50 lb Qu X ", measured clockwise from the positive z axis.
Please include a drawing
The magnitude of the three forces applied to the eye bolt are T1 = 550 N, T2 = 200 N and T3 =750 N. Solve the magnitude of the resultant force and the direction.
In the figure F1F2 are force vectors with magnitude shown. (A) Express each force in cartesian vector form (B) Determine the magnitude and coordinate direction angles of the resultant vector FR. (C) Draw the resultant vector. Make sure you label the axis, vector and angles. F = 125 N 60 45 60 F- 400 N F1 = 400 N , F2 = 125 N Need all three subparts detailed solution I want to learn how u got the answer
You must have to draw the FBD ,and then solve in handwritten format. [Don't Copy similar solution] Determine the moment of the force about point O. Neglect the thickness of the member. Assume F= 90N
Kindly show the complete step-by-step solution. I hope the picture of the asnwer will be clear. Please see the attached photo for the given problem. I will rate you with “like/upvote” after if its clear and understandable.
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Determine the r and y components of F, and F, acting on the boom shown in Fig. 2-18a. Express each force as a Cartesian vector. 158 F-200 N 200N fy 30 -fx Fx F 260 N 13 fy =F cos o 260 12 = 200 Cos (30) E 173.2 Fx = -f sino %3D - 200 Sin(30). %3D Fx Fooso %3D 12 = 260 () = 240 %3D 13 Fy=f Sino FR 이(음) M-260 13 -100 N

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