Part A - Practice Problem: Determine the gauge pressure for a 1.0-cm-diameter faucet located next to the washing machine in the basement, 2.6 m below where the pipe enters the house. Express your answer with the appropriate units. ?
Part A - Practice Problem: Determine the gauge pressure for a 1.0-cm-diameter faucet located next to the washing machine in the basement, 2.6 m below where the pipe enters the house. Express your answer with the appropriate units. ?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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<Homework 5 PHY 201 Spring - Attempt 1
Practice Problem 13.09 - Enhanced - with Feedback
14 of 15
SOLVE From the continuity equation, the flow speed v2 in the bathroom is
A1
V2 =
T(1.0 cm)?
T(0.50 cm)?
(2.0 m/s) = 8.0 m/s.
From Bernoulli's equation, the gauge pressure p2 in the bathroom is
pi - 5e(v2? – vi?) – pg(y2 – y1)
P2
4.0 × 105 Pa
=
-5(1.0 x 10° kg/m³)(64 m² /s² – 4.0 m² /s²)
2
-(1.0 x 10° kg/m³)(9.80 m/s²)(5.0 m)
3.2 x 105 Pa
3.2 atm = 47 lb/in.?
(gauge pressure).
The volume flow rate is
A2 v2 = T(0.50 × 10-2 m)² (8.0 m/s)
6.3 x 10-4 m³ /s = 0.63 L/s.
AV/At
The time needed to fill the tub is 100 L/(0.63 L/s) = 160 s.
REFLECT Note that when the water is turned off, the second term on the right of the pressure equation vanishes, and the pressure rises to 3.5 × 10° Pa. In fact, when the fluid is not moving, Bernoulli's equation reduces to
the pressure relationship that we derived for a fluid at rest.
Part A - Practice Problem:
Determine the gauge pressure for a 1.0-cm-diameter faucet located next to the washing machine in the basement, 2.6 m below where the pipe enters the house.
Express your answer with the appropriate units.
HÀ
Value
Units
Submit
Request Answer
Provide Feedback
Next"
Transcribed Image Text:10:38 PM Fri Apr 22
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b https://www.bartleby.com X
MasteringPhysics: Home X
G A piece of wood is floatin X
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A session.masteringphysics.com
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<Homework 5 PHY 201 Spring - Attempt 1
Practice Problem 13.09 - Enhanced - with Feedback
14 of 15
SOLVE From the continuity equation, the flow speed v2 in the bathroom is
A1
V2 =
T(1.0 cm)?
T(0.50 cm)?
(2.0 m/s) = 8.0 m/s.
From Bernoulli's equation, the gauge pressure p2 in the bathroom is
pi - 5e(v2? – vi?) – pg(y2 – y1)
P2
4.0 × 105 Pa
=
-5(1.0 x 10° kg/m³)(64 m² /s² – 4.0 m² /s²)
2
-(1.0 x 10° kg/m³)(9.80 m/s²)(5.0 m)
3.2 x 105 Pa
3.2 atm = 47 lb/in.?
(gauge pressure).
The volume flow rate is
A2 v2 = T(0.50 × 10-2 m)² (8.0 m/s)
6.3 x 10-4 m³ /s = 0.63 L/s.
AV/At
The time needed to fill the tub is 100 L/(0.63 L/s) = 160 s.
REFLECT Note that when the water is turned off, the second term on the right of the pressure equation vanishes, and the pressure rises to 3.5 × 10° Pa. In fact, when the fluid is not moving, Bernoulli's equation reduces to
the pressure relationship that we derived for a fluid at rest.
Part A - Practice Problem:
Determine the gauge pressure for a 1.0-cm-diameter faucet located next to the washing machine in the basement, 2.6 m below where the pipe enters the house.
Express your answer with the appropriate units.
HÀ
Value
Units
Submit
Request Answer
Provide Feedback
Next

Transcribed Image Text:Let's begin by looking at a flow problem in which the diameter of a pipe changes along the flow path. We will need to use both the continuity equation and Bernoulli's equation for this problem. Water enters a house through a
pipe with an inside diameter of 2.0 cm at a gauge pressure of 4.0 × 10° Pa (about 4 atm, or 60 lb/in.2). The cold-water pipe leading to the second-floor bathroom 5.0 m above is 1.0 cm in diameter . Find the flow speed
and gauge pressure in the bathroom when the flow speed at the inlet pipe is 2.0 m/s. How much time would be required to fill a 100 L bathtub with cold water?
To second floor
(1 cm pipe)
5.0 m
From water
Hot-water
supply
(2 cm pipe)
tank
SOLUTION
SET UP Let point 1 be at the inlet pipe and point 2 at the bathroom. The speed v2 of the water at the bathroom is obtained from the continuity equation, A1V1 = A2v2. We take y1
bathroom. We are given pi and v1; we can find p2 from Bernoulli's equation. To find the time required to fill the bathtub, we use the volume flow-rate relationship AV/At = Av. The bathtub's volume is
100 L = 100 × 10-3 m³.
0 at the inlet and y2
:5.0 m at the
SOLVE From the continuity equation, the flow speed v2 in the bathroom is
T(1.0 cm)?
A1
V1 =
A2
(2.0 m/s) = 8.0 m/s.
V2 =
7(0.50 cm)?
From Bernoulli's equation, the gauge pressure p2 in the bathroom is
P1 – 5P(v2² – vi²) – eg(y2 – y1)
P2
4.0 × 105 Pa
-(1.0 x 10° kg/m³)(64 m² /s² – 4.0 m² /s²)
2
-(1.0 x 10° kg/m³)(9.80 m/s²)(5.0 m)
3.2 x 105 Pa
3.2 atm
47 lb/in.?
(gauge pressure).
The volume flow rate is
AVLA
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