Problem 5.65 - Enhanced - with Feedback14 of 21I Review | Constants | Periodic TablePart AFrom the following enthalpies of reaction:H2(g) + F2(g) → 2HF(g),C(s) + 2F2 (g) → CF (g),ΔΗ-537 kJΔΗ-680 kJ2C(s) + 2H2(g) → C,H4(g),AH =+52.3 kJcalculate AH for the reaction of ethylene with F2:C2H4(g) + 6F2(g) → 2CF4(g) +4HF(g)Express your answer in kilojoules to three significant figures.ΔΗkJSubmitPrevious Answers Request Answer

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Part A From the following enthalpies of reaction: H2(g) + F2(g) → 2HF(g), C(s) + 2F2(g) → CF4(g), 2C(s) + 2H2(g) → CH«(g), ΔΗ -537 kJ %3D ΔΗ -680 kJ ΔΗ +52.3 kJ calculate AH for the reaction of ethylene with F2: C,H.(g) + 6F2(g) → 2CF4(g) + 4HF(g) Express your answer in kilojoules to three significant figures. ΑΣφ ΔΗ kJ Submit Previous Answers Request Answer

Part A From the following enthalpies of reaction: H2(g) + F2(g) → 2HF(g), C(s) + 2F2(g) → CF4(g), 2C(s) + 2H2(g) → CH«(g), ΔΗ -537 kJ %3D ΔΗ -680 kJ ΔΗ +52.3 kJ calculate AH for the reaction of ethylene with F2: C,H.(g) + 6F2(g) → 2CF4(g) + 4HF(g) Express your answer in kilojoules to three significant figures. ΑΣφ ΔΗ kJ Submit Previous Answers Request Answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What would be the product of the two electron oxidation of ethanol? The four-electron oxidation? Write balanced chemical equations for each, assuming that the process takes place in water and H2 gas is a product in each step.
Calculate AH for the following reaction, given the data in the table below: H2SO4() → So:(g) + H2O(g) AH = ??? kJ/mol H2S(g) +202(g)→ H2SO4(1) AH = -749.7 kJ H,S(g) + 202(g) → SO3(g) + H2O(1) AH = -355.0 kJ H20(1) H20(g) AH = +53.95 kJ
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D. NO₂(g) → N2(g) + O₂( 12. Use the graphs below to determine the enthalpy of reaction for the conversion of butane, C4H10, to butanol, C4H,OH. Enthalpy, H (kJ) Enthalpy Change during the Combustion Reaction of Butane C₂H₁0 + 13/20₂ AH -2881.9 kJ/mol 4CO₂+ 5H₂0 Reaction progress A. 169 kJ/mol B. -169 kJ/mol C. 5594.8 kJ/mol D. -5594.8 kJ/mol Enthalpy, H (kJ) Enthalpy Change during the Combustion Reaction of Butanol C,H,OH+60₂ AH=-2712.9 kJ/mol 4C0₂ + 5H₂0 Reaction progress obtained:
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