Review | Constants | PeriIodic TableThe standard heat of formation, Ar H°, is defined as the enthalpychange for the formation of one mole of substance from its constituentelements in their standard states. Thus, elements in their standardstates have AfH® =0. Heat of formation values can be used tocalculate the enthalpy change of any reaction.Part AFor which of the following reactions is A,H° equal to Ar H° of the product(s)?Consider, for example, the reactionYou do not need to look up any values to answer this question.2NO(g) + O2(9) = 2NO2(9)Check all that apply.with heat of formation values given by the following table:• View Available Hint(s)Substance(kJ mol-1)NO(9)O C(s) + 02 (9)→CO2(9)90.2O2 (9)O Li(s) + F2(1)→LIF(s)NO2(9)33.2O Li(s) + F2(9)→LİF(s)O 2Li(s) +F2(9)→2LİF(s)Then the heat of formation for the overall reaction isA,H°= EnpAf H° (products)- nA¢H° (reactants)O CO(g) + ÷O2(9)→CO2(9)2(33.2)[2(90.2) + 0]-114 kJ mol-1O BaCO3(s)→BA0(s) + CO2(9)Submit

Thermodynamics is the branch of chemistry which deals with the study of heat and other forms of…

Part A For which of the following reactions is A;H° equal to Af H° of the product(s)? You do not need to look up any values to answer this question. Check all that apply. • View Available Hint(s) O C(s) + O2 (9)→CO2(9) o Li(s) + F2(1)→LİF(s) O Li(s) + ¿F2(9)¬LİF(s) 2Li(s) + F2(9)→2LİF(s) O CO(g) + ¿O2(g)→CO2(9) O BACO3(s)→BAO(s) + CO2(9)

Part A For which of the following reactions is A;H° equal to Af H° of the product(s)? You do not need to look up any values to answer this question. Check all that apply. • View Available Hint(s) O C(s) + O2 (9)→CO2(9) o Li(s) + F2(1)→LİF(s) O Li(s) + ¿F2(9)¬LİF(s) 2Li(s) + F2(9)→2LİF(s) O CO(g) + ¿O2(g)→CO2(9) O BACO3(s)→BAO(s) + CO2(9)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Use the AH, information provided to calculate AH for the following: > SO,Cllg) + 2 H2O() AH, J/mol) 2 HCIG)+ H,S04) AH n 50,Cylg) -364 H,O -286 HCG) -92 H2SO -814 62 kJ 0-256 kJ 422 kJ O 256 kJ O -62 kJ
1. Using Hess's Law, calculate AH for this reaction: (T: 4) 2H3BO3(aq) →→→ B₂O3(s) + 3H₂O(l) (1) H₂BO3(aq) → HBO₂(aq) + H₂O(E) AH = -0.020 kJ (2) 2B₂O3(s) + H₂O(l) → H₂B4O7(s) AH = -17.5 kJ (3) H₂B4O7(s) + H₂O(l) → 4HBO₂(aq) AH = -11.3 kJ
You may want to reference (Pages 187 - 190) Section 5.7 while completing this problem. Part C Using values from Appendix C, calculate the value of AH° for each of the following reactions. 2CuO(s) +NO(g)→CU2O(s) +NO2 (g) Express your answer using three significant figures. ? ΔΗ3 kJ Submit Request Answer Part D 4NH3(g) + O2 (g)→2N2H4(g) +2H2O(1) Express your answer using five significant figures. ? AĦgm = kJ
Please answer question 12 part A
Calculate AH for the following reaction: IXI C(s) +H,0(g)→Co(g) - H, (3) Use the following reactions and given AH values: C(s) + O2 (g)→CO, (g), AH- 393.5 kJ 20(g) + 02 (g)→2CO2(g), AH = -566.0 kJ 2H2 (g) + O2 (g)→2H2O(g). AH = -483.6 kJ Express your answer using four significant figures.
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Answer letter a,b,c,d, and e pls.
Answer the following questions about compound a. Label the shortest C–C single bond. b. Label the longest C–C single bond. c. Considering all the bonds, label the shortest C–C bond. d. Label the weakest C–C bond. e.Label the strongest C–H bond. f.Explain why bond [1] and bond [2] are different in length, even though they are both C–C single bonds.
c) SO d) CO 0. Sodium reacts violently with water according to the equation: 2 Na(s) +2 H;0() 2 NaOH(aq) + H:(g) resulting solution has a higher temperature than the water prior to the addition of sodium. What are the signs of AH and AS for this reaction? a) AH is negative and AS is negative. b) AH is negative and AS is positive. e) AH is positive and AS is negative. d) AH is positive and AS is positive. (END)
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how to solve this problem using the given at the top
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