▼ Part A Compute the stopping sight distance available given a 550-ft curve, grades of g₁ = +2.00 % and g₂ = -2.50%, VPI at station 96 + 80, and elevation 845.26 ft, stakeout at full stations. Assume h₁ = 3.50 ft. and h₂ = 2.00 ft. Express your answer feet to five significant figures. ΠΫΠΙ ΑΣΦ S= Submit Request Answer vec 4 C ? ft

Q: A-2.40% grade meets a +1.50% grade at station 44+25 and elevation 3386.96 ft, 400-ft curve, stakeout…

A: The initial grade of the curve = -2.4% The final grade of the curve = +1.5% The station of point of…

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: Compute the passing sight distance available given a 440-ft curve, grades of g₁ = +2.00% and 9₂…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: A spiral is to be introduced to a 4-lane highway with a 2° 30' horizontal curve, maximum…

A: A curve, without sharp turns is a continuous and smooth line. The radius of curvature of the normal…

Q: Given a transition curve length of 85.500m, a design radius of 620.000m, a deflection angle of 95…

A: GIVEN DATA, Length of the  transition curve (l)= 85.5m design radius of the curve (R) = 620 m…

Q: A 500-ft curve, grades of g₁ = +1.50 % and g₂ = -2.50%, VPI at station 96 + 80 and elevation 841.26…

A: The initial grade of the curve = 1.5%The final grade of the curve = -2.50%The station of point of…

Q: Item 2 Grades of g₁ = -2.50% and 92 = +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 856 ftat 20+50 and y= 860 ft

Q: Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is…

A:

Q: rades of g₁= -0.50% and 92 +3.50 %, VPI elevation 750.00 ft at station 30+00. xed elevation 753.00…

A: Finding length and rate of grade change.

Q: A 500-ft curve, g₁ = -2.00%, 92 = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A:

Q: Compute the passing sight distance available given a 440-ft curve, grades of ₁₂ Express your answer…

A: The sight distance available from a point is the distance along the road surface over which a driver…

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: as of ₁-2.50% and 9₂ +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a foxed elevation…

A: g1= -2.50% g2= + 1.50% PVI Elevation = 856 ft at 20+50 and y= 860 ft

Q: elevation 854.00 ft at station 20 + 50. Field conditions require a highway curve to pass through a…

A:

Q: Field conditions require a highway curve to pass through a fixed point. Compute a suitable…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 868 ft and station = 22+00Fixed elevation, y = 872 ft and…

Q: A 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00 %, VPI at station 96 + 80 and elevation 851.26…

A: The initial grade of the curve = 2.5%The final grade of the curve = -3.0%The station of point of…

Q: Compute the stopping sight distance available given a 490-ft curve, grades of g₁ = +2.00% and 9₂ =…

A:

Q: For a highway curve with Da = 5°00', I = 20°30', and Pl station = 63 +25.53 ft, calculate the…

A: Given dataDegree of curve Da = 5°00'Intersection angle I = 20°30'PI station = 63+25.53 ft

Q: It is necessary to lay out the center line of a proposed road construction along Macapagal Avenue.…

A:

Q: Highway curve has R = 800 m, I = 20° 00', and Pl station 3+290.600 m. Part A Determine degree of…

A: R=800mdegree of curvature=?

Q: Answer fast

A: L = π * R * D / 180where:L is the length of the curve (m)R is the radius of the curve (m)D is the…

Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.