Part (a) Assuming the driver just barely avoids a collision, what is the final distance, in meters, between the car and the truck? Part (b) Enter an expression for the distance Ax₂ traveled by the truck in the time At, in terms of the quantities defined in the problem statement. Part (c) Find an expression for the distance ^x₁ traveled by the car in the time At, assuming the driver brakes as hard as they can. Part (d) Relate the total distance the car travels Ax₁ to the distance the truck travels and the initial distance between them. Part (e) Find the acceleration of the car in terms of its initial velocity,v₁, its final velocity, v2, and the time interval At. Part (f) Use your results from (b) through (e) to find a symbolic expression for the time At in terms of v₁, v2 and d. Part (g) Calculate the numerical value of At in seconds. Part (h) Using your result from (f), find a symbolic expression for the acceleration at. Part (1) Calculate the numerical value of az, in meters per second squared.
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
Please label and box answers.
![On a one lane road, a person driving a car at v₁ = 79 mi/h suddenly notices a
truck a distance d = 14 m in front of him. That truck is moving in the same direction at a constant
velocity of v₂ = 32 mi/h. In order to avoid a collision, the person in the car has to reduce their
speed to v2 in a time interval At. By slamming on their brakes, the driver can give the car a
maximum negative acceleration of ar. Assume the acceleration is constant and that the direction of
motion of the car is the nositive direction, so the acceleration ax < 0. Refer to the figure.
d
010-0
Part (a) Assuming the driver just barely avoids a collision, what is the final distance, in meters, between the car and the truck?
Part (b) Enter an expression for the distance Ax2 traveled by the truck in the time At, in terms of the quantities defined in the problem statement.
Part (c) Find an expression for the distance Ax₁ traveled by the car in the time At, assuming the driver brakes as hard as they can.
Part (d) Relate the total distance the car travels Ax₁ to the distance the truck travels and the initial distance between them.
Part (e) Find the acceleration of the car in terms of its initial velocity,v₁, its final velocity, v2, and the time interval At.
Part (f) Use your results from (b) through (e) to find a symbolic expression for the time At in terms of v₁, v2 and d.
Part (g) Calculate the numerical value of At in seconds.
Part (h) Using your result from (f), find a symbolic expression for the acceleration at.
Part (i) Calculate the numerical value of ag, in meters per second squared.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd49a5070-9d99-4a2f-a144-be47e7ddead5%2F8387d848-1565-47ac-95e7-bcb5f40a8eaf%2F29japw_processed.png&w=3840&q=75)
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