Part A A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? • View Available Hint(s) O Solution A: 1.81 % (mv) starch O Solution B: 6.89 % (m/v) starch Submit Part B A semipermeable membrane is placed between the following solutions. Which solution will increase in volume? > View Available Hint(s) O Solution C: 7.40 % NaCl Solution D: 14.6 % NaCl Submit Part C A red blood cell has been placed into each of three different solutions. One solution is isotonic to the cell, one solution hypotonic to the cell, and one solution is hypertonic to the cell. Sort each beaker into the appropriate bin based on the reaction in each solution.

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Learning Goal:
Part A
To learn about osmosis and about isotonic solutions,
hypertonic solutions, and hypotonic solutions.
A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume?
Osmosis is the net movement of water across a
semipermeable membrane from an area of lower
concentration to an area of higher concentration.
• View Available Hint(s)
(Figure 1)
O Solution A: 1.81 % (m/v) starch
The water will continue to move across the
O Solution B: 6.89 % (m/v) starch
semipermeable membrane as the system attempts to
reach equilibrium, where both solutions have the same
concentration.
Submit
There are three different ways a solution can be
described in relation to a cell placed in the solution:
isotonic, hypotonic, and hypertonic. Compared to a
cell, an isotonic solution exerts the same osmotic
pressure as the cellular fluids. In other words. it
Part B
A semipermeable membrane is placed between the following solutions. Which solution will increase in volume?
Figure
< 1 of 1
> View Available Hint(s)
Semipermeable
membrane
O Solution C: 7.40 % NaCl
Pure HO
NaCl(aq)
O Solution D: 14.6 % NaCl
Submit
H2O-
Time
H2O
H2O
-HO
Part C
A red blood cell has been placed into each of three different solutions. One solution is isotonic to the celI, one solution is
hypotonic to the cell, and one solution is hypertonic to the cell. Sort each beaker into the appropriate bin based on the cel
reaction in each solution.
Transcribed Image Text:Learning Goal: Part A To learn about osmosis and about isotonic solutions, hypertonic solutions, and hypotonic solutions. A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? Osmosis is the net movement of water across a semipermeable membrane from an area of lower concentration to an area of higher concentration. • View Available Hint(s) (Figure 1) O Solution A: 1.81 % (m/v) starch The water will continue to move across the O Solution B: 6.89 % (m/v) starch semipermeable membrane as the system attempts to reach equilibrium, where both solutions have the same concentration. Submit There are three different ways a solution can be described in relation to a cell placed in the solution: isotonic, hypotonic, and hypertonic. Compared to a cell, an isotonic solution exerts the same osmotic pressure as the cellular fluids. In other words. it Part B A semipermeable membrane is placed between the following solutions. Which solution will increase in volume? Figure < 1 of 1 > View Available Hint(s) Semipermeable membrane O Solution C: 7.40 % NaCl Pure HO NaCl(aq) O Solution D: 14.6 % NaCl Submit H2O- Time H2O H2O -HO Part C A red blood cell has been placed into each of three different solutions. One solution is isotonic to the celI, one solution is hypotonic to the cell, and one solution is hypertonic to the cell. Sort each beaker into the appropriate bin based on the cel reaction in each solution.
Expert Solution
Step 1

Principle

When a semipermeable membrane is placed between two solutions of different concentrations the solvent flows from the solution with a lower concentration to the solution with a higher concentration. As a result the volume of the solution with lower concentration decreases and the volume of the solution with higher concentration increases.

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