Part A=A 600-ft curve, grades of g, -1.50% and92 = -2.25%, VPI at station 38+00, and elevation168.00 ft, stakeout at full stations.List station elevations, including BVC and EVC, for an equal-tangent parabolic curve for the data given.Give the elevations in order of increasing X.Express your answers in feet to five significant figures separated by commas.Elev =ΜΕ ΑΣΦvedSubmitRequest Answer| ?ft

Final Answer (Elevations at Each Station):172.50, 170.94, 169.25, 167.44, 165.50, 163.44, 161.25…

Answered: Part A = A 600-ft curve, grades of g,…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A-2.40% grade meets a +1.60% grade at station 44+25 and elevation 3387.96 ft, 400-ft curve, stakeout at half stations. Part A Tabulate station elevations for an equal-tangent parabolic curve for the data given above. Express your answers in feet to six significant figures separated by commas in order of increasing station numbers. {—| ΑΣΦ | 11 | vec A Elev= 3412.46,3432.72,3450.30,3465.20,3477.45 ft Your submission doesn't have the correct number of answers. Answers should be separated with a comma. No credit lost. Try again. Submit Previous Answers Request Answer Provide Feedback Review ? Next >
A-2.60% grade meets a +1.70% grade at station 44+25 and elevation 3387.96 ft, 400-ft curve, stakeout at half stations. Part A Tabulate station elevations for an equal-tangent parabolic curve for the data given above. Express your answers in feet to six significant figures separated by commas in order of increasing station numbers. Elev = Submit ΑΣΦ ↓↑ Request Answer vec ? ft
A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 162.657 m, 180-m curve, stakeout at 30-m increments. List station elevations, including BVC and EVC, for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X. Express your answers in meters to six significant figures separated by commas.
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%3D A horizontal curve has a radius of 980.80 ft.; an I = 23°00'00"; and, PC Station %3D 76+68.50 ft. Determine: • Deflection angle from the PC to station 79+00.00 ft. = Provide the answer in degrees, minutes, and seconds. Provide whole numbers and do not include units. • Chord length from the PC to station 79+00.00 ft.= Provide your answer to two decimal places and do not include units. • Straight line distance from the PC to the PI = Provide %3D your answer to two decimal places and do not include units.
Given a simple circular curve, in feet, with the following known information: o | = 25°10'45" Da = 8°15'00" o STA P.I. = 30+89.45 What is the stationing of the C.T.? O 32+39.55 32+39.68 36+97.40 O 33+94.65
A500-ft curve, grades of g +2.50% and ₂-2 50% VPI at station 96 00 and elevation 839 26 ft, stakeout at full stations A Part A List station elevations for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X Express your answers in feet to five significant figures separated by commas. Elev ΚΕΙ ΑΣΦ | Η vec 5 Ĉ 2 ft
A 600-ft curve, grades of g₁ = -1.00% and 92 = -2.25%, VPI at station 38 +00, and elevation 154.00 ft, stakeout at full stations. Part A List station elevations for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X. Express your answers in feet to five significant figures separated by commas. Elev = Submit 17| ΑΣΦ ↓↑ vec Request Answer ? ft
1. A proposed road bend along a highway construction project is to be laid out such that it will be a circular simple curve tangent to the three reference lines DA, AB, and BC. From the given data below, calculate for the following. a. radius of the simple curve b. stationing of PC if V is at 12 + 340 c. stationing of PT POINT LATITUDE DEPARTURE A - 29.34 - 128.76 B - 177.97 - 58.39 Bearing DA = S65°01'50"E Bearing CB = N54°24'10"E
Given the following level section notes for stations 1+120 and 1+160: 1+120 | 6.6 | 0 | 7.6 | 0.8 | 3.7 | 1.3 1+160 | 74 | 0 | 98 | 1.2 | 2.3 | 2.4 The side slope is 2:1. The radius of curvature is 275 m. The center of curvature is on the right. a) What is the roadbed width? b) What is the area of section 1+120? c) What is the area of section 1+160? d) What is the volume between section 1+120 and 1+160 using end area method? e) What is the prismoidal volume correction? g) What is the centroid of excess of section 1+160? h) What is the correction due to horizontal curvature?
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