Part A (1 of 2) Draw the curved arrows for Step 4 of this mechanism. Arrow-pushing Instructions CH3 H. CH3 Н. Step 4 :Br: H N=c=ö: :N Br: Recheck Next (1 of 2) 3rd attempt Inco Double-headed arrows denote the movement of a pair of electrons, so an arrow must start from either a bond or a lone pair. There are 3 arrows in this step.
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![Part A (1 of 2) Draw the curved arrows for Step 4 of this mechanism.
Arrow-pushing Instructions
CH3
H.
CH3
Н.
:Br:
Step 4
:N
N=c=ö:
Next (1 of 2)
Recheck
3rd attempt
Incorrect
Double-headed arrows denote the movement of a pair of electrons, so an arrow must start from either a bond or a lone pair.
There are 3 arrows in this step.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe052c52d-191b-4c56-87c8-13d2ed02903f%2Fa0458aa9-aca6-45ea-a3b5-359ebb43fd2e%2Fxz0tyht_processed.png&w=3840&q=75)
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