Part 4 (problem solving) Problem 1 Calculate sag correction for a 30 m steel tape under a pull of 80 N, if it is suspended in three equal spans. Unit weight of steel is 78.6 kN/m3. Area of cross-section of tape is 8 mm2.

The structural frame below is loaded as shown. Determine the required area for members AB, ED,CD, AF, and FG considering the material’sproperty below : E= 200GPa, Allowable Stress for Compression is 120MPa and 315MPa for tension. Note : all units in meters.

Determine the losses in the post-tensioned concrete beam as shown below. 560 mm Given: POST-TENSIONED BEAM with A PARABOLIC TENDON PROFILE Span Length = 20 m fi = 1200 N/mm² A, = 2850 mm² Ac 4.23x105 mm² 1=9.36x10¹0 mm e-560 mm (@midspan, from N.A.) fc= 40 N/mm² Es = 210,000 N/mm² μ = 0.19 K = 0.0005 (per meter) Anchorage slip = 5 mm (jacked at left-end only). (make sure to draw the force variation diagram for anchorage slip) V/S= 6 RH = 70 Dead Load 9.97 kN/m fpy = 1714 N/mm² Bridge Width III