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Part 4 of 6- Categorize: (6) From the correct choice in question (2) above, what equation will be most useful in determining the height reached by the ball? • E v - v - 29r, - v) y Vy - gt Part 6 of 6 - Analyze: (cont.) none of the above (8) From the correct choice in question (7) above, substitute numerical values to find the maximum height of Correct. This equation contains ye which we would like to find, and other quantities, all of which we know. the ball as observed by the professor. Part 5 of 6- Categorize: 2g (7) From the correct choice in question (6), find an expression for the maximum height y, of the ball in terms of v the initial vertical velocity as seen by the professor. ]m/s)² )m/s?) Vyi %3D

Part 4 of 6- Categorize: (6) From the correct choice in question (2) above, what equation will be most useful in determining the height reached by the ball? • E v - v - 29r, - v) y Vy - gt Part 6 of 6 - Analyze: (cont.) none of the above (8) From the correct choice in question (7) above, substitute numerical values to find the maximum height of Correct. This equation contains ye which we would like to find, and other quantities, all of which we know. the ball as observed by the professor. Part 5 of 6- Categorize: 2g (7) From the correct choice in question (6), find an expression for the maximum height y, of the ball in terms of v the initial vertical velocity as seen by the professor. ]m/s)² )m/s?) Vyi %3D

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Part 4 of 6 - Categorize: (6) From the correct choice in question (2) above, what equation will be most useful in determining the height reached by the ball? Y, - Y; + vyt -gt² P v - v - 29(y; - Y) Vyr = Vy - gt Y = Y; +(vyi + vy)t Part 6 of 6 - Analyze: (cont.) none of the above (8) From the correct choice in question (7) above, substitute numerical values to find the maximum height of Correct. This equation contains ye which we would like to find, and other quantities, all of which we know. the ball as observed by the professor. Yf = 2g Part 5 of 6- Categorize: (7) From the correct choice in question (6), find an expression for the maximum height y, of the ball in terms of v vi the initial vertical velocity as seen by the professor. mvs) m/s²) Vyi m 29 29
Transcribed Image Text:Part 4 of 6 - Categorize: (6) From the correct choice in question (2) above, what equation will be most useful in determining the height reached by the ball? Y, - Y; + vyt -gt² P v - v - 29(y; - Y) Vyr = Vy - gt Y = Y; +(vyi + vy)t Part 6 of 6 - Analyze: (cont.) none of the above (8) From the correct choice in question (7) above, substitute numerical values to find the maximum height of Correct. This equation contains ye which we would like to find, and other quantities, all of which we know. the ball as observed by the professor. Yf = 2g Part 5 of 6- Categorize: (7) From the correct choice in question (6), find an expression for the maximum height y, of the ball in terms of v vi the initial vertical velocity as seen by the professor. mvs) m/s²) Vyi m 29 29
Analysis Model Tutorial Part 3 of 6 - Analyze: (3) If the flatcar is moving along the x axis with a velocity of +17.0 m/s, and the ball is thrown so that the A science student is riding on a flatcar of a train traveling along a straight, horizontal track at a constant professor on the ground sees the ball rise vertically, what must be the x component of the initial velocity with speed of 17.0 m/s. The student throws a ball into the air along a path that he judges to make an initial angle which the student threw the ball, relative to the flatcar? of 44.0° with the horizontal and to be in line with the track. The student's professor, who is standing on the O P 1-17.0 m/s ground nearby, observes the ball to rise vertically. How high does she see the ball rise? (-17.0 m/s)cos 44.0° (+17.0 m/s)cos 44.0° Part 1 of 6 - Conceptualize: Imagine the scene and clarify in your mind the positions of the two observers, the student and the professor. +17.0 m/s The student sees the ball being launched at an angle of 44.0° with respect to the horizontal. The professor, on none of the above the other hand, sees the ball rise vertically, with no horizontal component of velocity. (1) In order for the professor to see the ball rise vertically, the ball must be thrown in a direction that is Correct. The velocity of the ball relative to the ground, as observed by the professor, is zero in this case. (4) What is the initial vertical velocity component of the ball as observed by the student? backward backward with respect to the velocity with which the student is moving relative to the (+17.0 m/s)tan 44.0° = 16.4 m/s ground. Based on human limits on throwing objects, we expect the height of the throw to be measured in values no O (-17.0 m/s)tan 44.0° = -16.4 m/s more than a few tens of meters. (17.0 m/s)cos 44.0° = 12.2 m/s (17.0 m/s)sin 44.0° = 11.8 m/s Part 2 of 6 - Categorize: none of the above In the Conceptualize step, we have seen that we need to categorize the problem as one involving relative velocities. We also see that the motion of the ball as observed by the professor is vertical. Correct. This is the correct initial vertical velocity component of the ball as observed by the student. (5) What is the initial vertical velocity component of the ball as observed by the professor? (2) What analysis model correctly describes the motion of the ball in the vertical direction as observed by the 12.2 m/s professor? particle under constant velocity O -16.4 m/s O P particle under constant acceleration O D 16.4 m/s
Transcribed Image Text:Analysis Model Tutorial Part 3 of 6 - Analyze: (3) If the flatcar is moving along the x axis with a velocity of +17.0 m/s, and the ball is thrown so that the A science student is riding on a flatcar of a train traveling along a straight, horizontal track at a constant professor on the ground sees the ball rise vertically, what must be the x component of the initial velocity with speed of 17.0 m/s. The student throws a ball into the air along a path that he judges to make an initial angle which the student threw the ball, relative to the flatcar? of 44.0° with the horizontal and to be in line with the track. The student's professor, who is standing on the O P 1-17.0 m/s ground nearby, observes the ball to rise vertically. How high does she see the ball rise? (-17.0 m/s)cos 44.0° (+17.0 m/s)cos 44.0° Part 1 of 6 - Conceptualize: Imagine the scene and clarify in your mind the positions of the two observers, the student and the professor. +17.0 m/s The student sees the ball being launched at an angle of 44.0° with respect to the horizontal. The professor, on none of the above the other hand, sees the ball rise vertically, with no horizontal component of velocity. (1) In order for the professor to see the ball rise vertically, the ball must be thrown in a direction that is Correct. The velocity of the ball relative to the ground, as observed by the professor, is zero in this case. (4) What is the initial vertical velocity component of the ball as observed by the student? backward backward with respect to the velocity with which the student is moving relative to the (+17.0 m/s)tan 44.0° = 16.4 m/s ground. Based on human limits on throwing objects, we expect the height of the throw to be measured in values no O (-17.0 m/s)tan 44.0° = -16.4 m/s more than a few tens of meters. (17.0 m/s)cos 44.0° = 12.2 m/s (17.0 m/s)sin 44.0° = 11.8 m/s Part 2 of 6 - Categorize: none of the above In the Conceptualize step, we have seen that we need to categorize the problem as one involving relative velocities. We also see that the motion of the ball as observed by the professor is vertical. Correct. This is the correct initial vertical velocity component of the ball as observed by the student. (5) What is the initial vertical velocity component of the ball as observed by the professor? (2) What analysis model correctly describes the motion of the ball in the vertical direction as observed by the 12.2 m/s professor? particle under constant velocity O -16.4 m/s O P particle under constant acceleration O D 16.4 m/s
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