Part 4 of 6-Analyze (b) The electric field between the capacitor plates is given by E = 0/ɛ so we have 8.85 x 10-12 c2/N m2)( 1.19 10ʻ V/m) 05315 Your response is off by a multiple of ten. × 10 8 C/m² = nC/m².

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I need help with the calculation please.
**Part 4 of 6 - Analyze**

**(b) The electric field between the capacitor plates is given by \( E = \sigma / \varepsilon_0 \), so we have:**

\[ \sigma = \varepsilon_0 E \]

\[ = \left( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \right) \left( 1.19 \times 10^4 \, \text{V/m} \right) \]

\[ = 05315 \times 10^{-8} \, \text{C/m}^2 = \boxed{ } \, \text{nC/m}^2. \]

**Explanation:**

1. **Equation Explanation:** The given equation \( E = \sigma / \varepsilon_0 \) describes the electric field \( E \) between capacitor plates in terms of the surface charge density \( \sigma \) and the permittivity of free space \( \varepsilon_0 \).
2. **Given Values:** The permittivity of free space (\( \varepsilon_0 \)) is \( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \), and the electric field \( E \) is \( 1.19 \times 10^4 \, \text{V/m} \).
3. **Multiplication Step:** The above values are multiplied, giving an intermediate answer in units of \( \text{C/m}^2 \).
4. **Error Notification:** The response "05315" is flagged as off by a multiple of ten, suggesting a common mistake when dealing with scientific notation.
5. **Conversion to nC/m²:** The final part involves correcting the intermediate answer and converting it to nanocoulombs per square meter (nC/m²).

The input field labeled \(\boxed{ }\) indicates where the correct answer should be filled once the calculation is corrected.

**Note:** The response box seems intended for user interaction, emphasizing the importance of precision in handling scientific notation and unit conversion.
Transcribed Image Text:**Part 4 of 6 - Analyze** **(b) The electric field between the capacitor plates is given by \( E = \sigma / \varepsilon_0 \), so we have:** \[ \sigma = \varepsilon_0 E \] \[ = \left( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \right) \left( 1.19 \times 10^4 \, \text{V/m} \right) \] \[ = 05315 \times 10^{-8} \, \text{C/m}^2 = \boxed{ } \, \text{nC/m}^2. \] **Explanation:** 1. **Equation Explanation:** The given equation \( E = \sigma / \varepsilon_0 \) describes the electric field \( E \) between capacitor plates in terms of the surface charge density \( \sigma \) and the permittivity of free space \( \varepsilon_0 \). 2. **Given Values:** The permittivity of free space (\( \varepsilon_0 \)) is \( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \), and the electric field \( E \) is \( 1.19 \times 10^4 \, \text{V/m} \). 3. **Multiplication Step:** The above values are multiplied, giving an intermediate answer in units of \( \text{C/m}^2 \). 4. **Error Notification:** The response "05315" is flagged as off by a multiple of ten, suggesting a common mistake when dealing with scientific notation. 5. **Conversion to nC/m²:** The final part involves correcting the intermediate answer and converting it to nanocoulombs per square meter (nC/m²). The input field labeled \(\boxed{ }\) indicates where the correct answer should be filled once the calculation is corrected. **Note:** The response box seems intended for user interaction, emphasizing the importance of precision in handling scientific notation and unit conversion.
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