If a = 4.3 m and b = 7.7 m. Find the magnitude of Fi+F2 give the magnitude F1 =28 N and and F2=37.7 N. Round your answer to 1 decimal place.

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Chapter1: Units, Trigonometry. And Vectors
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### Vector Addition Problem

#### Given:
- Distance \(a = 4.3 \, \text{m}\)
- Distance \(b = 7.7 \, \text{m}\)
- Magnitude of vector \(\mathbf{F}_1 = 28 \, \text{N}\)
- Magnitude of vector \(\mathbf{F}_2 = 37.7 \, \text{N}\)

#### Objective:
Find the magnitude of the resultant vector \(\mathbf{F}_1 + \mathbf{F}_2\). Round your answer to one decimal place.

#### Explanation:
The accompanying diagram represents a vector problem in a coordinate system where:
- \(\mathbf{F}_1\) is a force vector directed at an angle above the horizontal axis.
- \(\mathbf{F}_2\) is a force vector directed horizontally to the left.

The distances \(a\) and \(b\) are used to determine the direction of the forces:
- Distance \(a\) is the horizontal component of vector \(\mathbf{F}_1\).
- Distance \(b\) is the vertical component of vector \(\mathbf{F}_1\).

The task is to determine the resultant vector by summing these two vectors and finding the magnitude of the resultant.

#### Steps:
1. **Determine the Components of Vectors:**
   - For \(\mathbf{F}_1\): Given the right triangle formed by \(a\) and \(b\), use trigonometric relations to find the components.
     \[
     \text{angle} \theta = \tan^{-1} \left( \frac{b}{a} \right) = \tan^{-1} \left( \frac{7.7}{4.3} \right)
     \]
     Use this angle \(\theta\) to resolve \(\mathbf{F}_1\) into components:
     \[
     F_{1x} = F_1 \cos(\theta) \quad \text{and} \quad F_{1y} = F_1 \sin(\theta)
     \]

2. **Vector Addition:**
   \[
   \mathbf{F}_{\text{total}} = \mathbf{F}_1 + \mathbf{F}_2
   \]
   Find the total x and y components:
   \[
   F_{\text{total},
Transcribed Image Text:### Vector Addition Problem #### Given: - Distance \(a = 4.3 \, \text{m}\) - Distance \(b = 7.7 \, \text{m}\) - Magnitude of vector \(\mathbf{F}_1 = 28 \, \text{N}\) - Magnitude of vector \(\mathbf{F}_2 = 37.7 \, \text{N}\) #### Objective: Find the magnitude of the resultant vector \(\mathbf{F}_1 + \mathbf{F}_2\). Round your answer to one decimal place. #### Explanation: The accompanying diagram represents a vector problem in a coordinate system where: - \(\mathbf{F}_1\) is a force vector directed at an angle above the horizontal axis. - \(\mathbf{F}_2\) is a force vector directed horizontally to the left. The distances \(a\) and \(b\) are used to determine the direction of the forces: - Distance \(a\) is the horizontal component of vector \(\mathbf{F}_1\). - Distance \(b\) is the vertical component of vector \(\mathbf{F}_1\). The task is to determine the resultant vector by summing these two vectors and finding the magnitude of the resultant. #### Steps: 1. **Determine the Components of Vectors:** - For \(\mathbf{F}_1\): Given the right triangle formed by \(a\) and \(b\), use trigonometric relations to find the components. \[ \text{angle} \theta = \tan^{-1} \left( \frac{b}{a} \right) = \tan^{-1} \left( \frac{7.7}{4.3} \right) \] Use this angle \(\theta\) to resolve \(\mathbf{F}_1\) into components: \[ F_{1x} = F_1 \cos(\theta) \quad \text{and} \quad F_{1y} = F_1 \sin(\theta) \] 2. **Vector Addition:** \[ \mathbf{F}_{\text{total}} = \mathbf{F}_1 + \mathbf{F}_2 \] Find the total x and y components: \[ F_{\text{total},
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