Part 3 Determine the bending moment acting at each of the following locations: (a)x-11.5-ft (i.e, just to the left of point B) (b) x-11.5+ ft(i.e, just to the right of point B) (c)x-17.5 ft (i.e. at point C) (d) x - 23.0 ft Note that x - O at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. Answers: (a) M- (b) M- (c) M- (d) M- Part 4 Answers: Mmax pos i Max, neg i kips-ft Use your shear-force and bending-moment diagrams to determine the maximum positive bending moment, Mmax.pos, the maximum negative bending moment, Max, nes and their respective locations, Xmax.pos and xmax, nes When entering your answers for the maximum bending moments, use the shear-force and bending-moment sign conventions detailed in Section 7.2. The maximum negative bending moment is the negative moment with the largest absolute value. Enter the maximum negative bending moment as a negative value. i kips-ft kips-ft kips-ft kips-ft Xmax.pos kips-ft Xmaxnes i ft ft

For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.)  Let w = 19.5 kips/ft, a=6.0 ft, and b=21.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces By and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Bx = 0, it has been omitted from the free-body diagram.) Determine the bending moment acting at each of the following locations:(a) x = 6.0 ft (i.e., at support B)(b) x = 26.5 ftNote that x = 0 at point A.  When entering your answers, use the bending-moment sign convention detailed in Section 7.2.Answers: (a) M =  kips-ft (b) M =  kips-ft

For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. Place the origin at point A. Let a=4.00 m, b=5.25 m, c= 2.50 m, P = 26kN and M = 160kN-m. Construct the shear-force and bending-moment diagrams. Use the bending-moment diagram to determine the maximum positive bending moment, Mmax, pos, and the maximum negative bending moment, Mmax, neg.

Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=5.0 m, MB = 110 kN-m and MC = 145 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)Determine the shear force acting at each of the following locations:(a) x = 0+ m (i.e., just to the right of point A)(b) x = 3.5– m (i.e., just to the left of B)(c) x = 3.5+ m (i.e., just to the right of B)(d) x = 12.0– m (i.e., just to the left of D)When entering your answers, use the shear force sign convention.Answers:(a) V =  kN.(b) V =  kN.(c) V =  kN.(d) V =  kN.

Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 m, b=5.0 m, MB = 110 kN-m and MC = 145 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)Determine the bending moment acting at each of the following locations:(a) x = 3.5– m (i.e., just to the left of B)(b) x = 3.5+ m (i.e., just to the right of B)(c) x = 8.5– m (i.e., just to the left of C)(d) x = 8.5+ m (i.e., just to the right of C)When entering your answers, use the bending moment sign convention.Answers:(a) M =  kN-m.(b) M =  kN-m.(c) M =  kN-m.(d) M =  kN-m.

Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 m, b=2.5 m, PB = 4 kN, PC = 4 kN, and MB = 60 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and MA acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Determine the bending moment acting at each of the following locations:(a) x = 0+ m (i.e., just to the right of fixed support A)(b) x = 4.0– m (i.e., just to the left of B)(c) x = 4.0+ m (i.e., just to the right of B)(d) x = 6.5 mWhen entering your answers, use the bending moment sign convention.Answers:(a) M =  kN-m.(b) M =  kN-m.(c) M =  kN-m.(d) M =  kN-m.

For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.)  Let w = 4.0 kips/ft, a= 6.5 ft, and b= 17.5 ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.

For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let a=2.75 m, b=5.00 m, PB = 60KN, and Pc = 80kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Answers: Ay = Dy= tel tel a i B a Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) PB B a PB Pc a C Pc C KN b KN D b D X D₂ X

For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=8.5 ft, b=24.0 ft, P = 30 kips and w = 5.5 kips/ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Determine the shear force acting at each of the following locations:(a) x = 8.5- ft (i.e., just to the left of point B)(b) x = 8.5+ ft (i.e., just to the right of point B)(c) x = 30.5 ftNote that x = 0 at support A.  When entering your answers, use the shear-force sign convention detailed in Section 7.2. Determine the bending moment acting at each of…

For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a-3.25 m, b=4.75 m, Pg - 35kN, and Pc = 80kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A Ay- 58.66 - Dy- Calculate the reaction forces A, and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Answers: a 56.33 (a) V= (b) V- (c) V- B i i PB B kN с kN C Determine the shear force acting at each of the following locations: (a) x-2m (b)x - 4 m (c) x-8 m Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. 3 3 3 KN D b kN D ·x Dy