Part 2 of 2 Use the small angle formula to calculate the linear diameter of the globular cluster. angular diameter 2.06 x 105 We must first convert the angular diameter into arc seconds. 8 = (a)( 60 arc seconds 1 arc minute D arc seconds If we want our answer in parsecs we should convert the distance from kiloparsecs to parsecs (1 kpc = 1,000 pc). pc Dpc Solving for the linear diameter (in pc) gives: d = Dpc 2.06 x 10 pc

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Can you please help with Part 2 of 2? Thank you.

A globular cluster contains an RR Lyrae star with an observed pulsation period of 16 hours and an average apparent magnitude of 17.2.
What is the distance (in kpc) to the globular cluster?
If you measure the angular diameter to be 20 arc minutes, what is the linear diameter (in pc)?
Part 1 of 2
To determine the distance to the globular cluster, you need to use the magnitude-distance formula:
=10(m-M+5)/5
D=
We can use the figure below to estimate the absolute magnitude of the RR Lyrae star.
Absolute magnitude
4
-6
-5
0.3
Type
(classical)
Cephelds
& Cephel-
Type II
Cepheids
RR Lyrae stars
1
3
10
Pulsation period (days)
30
104
103
10²
100
Luminosity, L/LO
e
Transcribed Image Text:A globular cluster contains an RR Lyrae star with an observed pulsation period of 16 hours and an average apparent magnitude of 17.2. What is the distance (in kpc) to the globular cluster? If you measure the angular diameter to be 20 arc minutes, what is the linear diameter (in pc)? Part 1 of 2 To determine the distance to the globular cluster, you need to use the magnitude-distance formula: =10(m-M+5)/5 D= We can use the figure below to estimate the absolute magnitude of the RR Lyrae star. Absolute magnitude 4 -6 -5 0.3 Type (classical) Cephelds & Cephel- Type II Cepheids RR Lyrae stars 1 3 10 Pulsation period (days) 30 104 103 10² 100 Luminosity, L/LO e
Based on the figure,
M = 0.5✔
Use the given average apparent magnitude to solve for the distance (in kpc).
D
10(m-M+5)/5
D 21.87✔
0.5
Part 2 of 2
Use the small angle formula to calculate the linear diameter of the globular cluster.
angular diameter d
2.06 x 105
e = (a)(-
8=
We must first convert the angular diameter into arc seconds.
60 arc seconds
1 arc minute
21.9 kpc
d=
arc seconds
If we want our answer in parsecs we should convert the distance from kiloparsecs to parsecs (1 kpc = 1,000 pc).
pc
Solving for the linear diameter (in pc) gives:
0
2.06 x 10
d=
pc
Transcribed Image Text:Based on the figure, M = 0.5✔ Use the given average apparent magnitude to solve for the distance (in kpc). D 10(m-M+5)/5 D 21.87✔ 0.5 Part 2 of 2 Use the small angle formula to calculate the linear diameter of the globular cluster. angular diameter d 2.06 x 105 e = (a)(- 8= We must first convert the angular diameter into arc seconds. 60 arc seconds 1 arc minute 21.9 kpc d= arc seconds If we want our answer in parsecs we should convert the distance from kiloparsecs to parsecs (1 kpc = 1,000 pc). pc Solving for the linear diameter (in pc) gives: 0 2.06 x 10 d= pc
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