Problem 2This problem is composed of two independent parts.For all parts of this problem, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLYA NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS).Please check and confirm these answers in Part 1 and Part 2Part 1Visible light of frequency f = 5 x 10¹4 Hz is beamed directly at a metal reflector. Light is traveling in oil,where its speed is 1.5 × 108 m/s.a)Calculate the wavelength of the visible light.A =3x10^(-7) mConsider λ = 6 x 10-7 m. The spacing Ax between successive antinodes in the resultingstanding-wave pattern is given by:b)6 × 10-72c)Δι' = 3x10^(-7) mCalculate Ar.E₁ =200Part 2A standing wave is given by E= 400 sin( 7.14 x) cos( 11.42 t). Two waves E₁ and E2 can besuperimposed to generate this standing wave.6 x 10-73Determine the wave E₁ as per the below:sin 7.14t)11.42Determine the wave E2 as per the below:sin 7.14x + 11.42 t)m6 x 10-74b)E2 = 200c)The wavelength of this wave is 0.87 m. For a > 0, what is the location of the antinodehaving the smallest value of a?x = 0.2175

Part1. Given,The frequency, The speed, a. The wavelength of the visible light,

Answered: Part 1 Visible light of frequency f = 5…

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