#3Part 1 of 4The mean number of English courses taken in a two-year time period by male and female collegestudents is believed to be about the same. An experiment is conducted and data are collected from26 males and 20 females. The males took an average of 3.7 English courses with a standarddeviation of 0.3. The females took an average of 3.6 English courses with a standard deviation of 0.6.Conduct a hypothesis test at the 1% level of significance to determine whether the means arestatistically the same.Step 1: State the null and alternative hypotheses.Ho: 12V0Ha: 1₂ VO(So we will be performing a two-tailedEPart 2 of 4Step 2: Assuming the null hypothesis is true, determine the features of the distribution of thedifferences of sample means.The differences of sample means are t-distributedand distribution standard deviation 1Question Help: Post to forumSubmit Part$4R✓✓test.)%5TxSearch or type URL✔with distribution mea 06&7U* 008+TC-

An experiment is conducted and data are collected from 26 males and 20 females. The males took an…

Answered: Part 1 of 4 The mean number of English…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a research study, American teenagers watched 14.8 hours of television per week last year, on average. A random sample of 11 American teenagers was surveyed and the mean amount of time per week each teenager watched television was 15.6. This data has a sample standard deviation of2.5. (Assume that the scores are normally distributed.) Researchers conduct a one-mean hypothesis test at the 5% significance level, to test if the mean amount of time American teenagers watch television per week is greater than the mean amount of time last year. (a) Ho : μ-148; Ha : μ 14.8, which is a right-tailed test. (b) Determine the test statistic, rounded to two decimal places. Provide your answer below: Test statistic
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A sample of 100 observations has a sample mean of 500 and a sample standard deviation of 50. Conduct a hypothesis test to determine if the population mean is equal to 480 at a significance level of 0.05.
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Location is known to affect the number, of a particular item, sold by HEB Pantry. Two different locations, A and B, are selected on an experimental basis. Location A was observed for 18 days and location B was observed for 18 days. The number of the particular items sold per day was recorded for each location. On average, location A sold 39 of these items with a sample standard deviation of 9 and location B sold 55 of these items with a sample standard deviation of 6. Does the data provide sufficient evidence to conclude that the true mean number of sales at location A exceeds the true mean number of sales at location B at the 0.01 level of significance? Select the [Alternative Hypothesis, Value of the Test Statistic]. a) [μ1 − μ2 ≠ 0, t = −6.276] b) [μ1 − μ2 = 0, -6.277] c) [μ1 − μ2 ≠ 0, -0.6277] d) [μ1 − μ2 > 0, t = −6.276] e) [μ1 − μ2 < 0, t = −6.276] f) None of the above
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A study was designed to compare the attitudes of two groups of nursing students towards computers. Group 1 had previously taken a statistical methods course that involved significant computer interaction. Group 2 had taken a statistic methods course that did not use computers. The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 9 nursing students from Group 1 resulted in a mean score of 65 with a standard deviation of 6.2. A random sample of 7 nursing students from Group 2 resulted in a mean score of 74.2 with a standard deviation of 8.9. Can you conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2? Let uj represent the mean score for Group 1 and uz represent the mean score for Group 2. Use a significance level of a = 0.01 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 4: State the null and alternative…

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