Part 1 of 3 The circular velocity equation can be used to determine the orbital velocity of a ring particle. GM Calculate the orbital velocity of a ring particle that orbits 1.25 x 10° km from the center of Jupiter. GM %3D km/s

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**Educational Content:**

**Calculate the Orbital Velocity**

Calculate the orbital velocity (in km/s) of a ring particle that orbits \( 1.25 \times 10^5 \) km from the center of Jupiter.

**Roche Limit for Jupiter**

What is the Roche limit (in km) for Jupiter?

**Find the Closest Moon**

Find the moon in the table below that is closest to this radius. What is its orbital velocity (in km/s)?

---

**Selection of Principal Satellites of the Solar System**

| Primary | Satellite   | Radius (km)   | Distance from Primary (10^3 km) |
|---------|-------------|---------------|---------------------------------|
| **Jupiter** | Amalthea  | 135 × 100 × 78 | 182                             |
|         | Io          | 1,820         | 422                             |
|         | Europa      | 1,560         | 671                             |
|         | Ganymede    | 2,630         | 1,071                           |
|         | Callisto    | 2,410         | 1,884                           |
|         | Himalia     | ~85           | 11,470                          |
| **Saturn** | Janus      | 110 × 80 × 100| 151.5                           |
|         | Mimas       | 196           | 185.5                           |
|         | Enceladus   | 260           | 238.0                           |
|         | Tethys      | 530           | 294.7                           |
|         | Dione       | 560           | 377                             |
|         | Rhea        | 765           | 527                             |
|         | Titan       | 2,575         | 1,222                           |
|         | Hyperion    | 205 × 130 × 110| 1,484                           |
|         | Iapetus     | 720           | 3,562                           |
|         | Phoebe      | 105           | 12,930                          |

---

The table lists some principal satellites of Jupiter and Saturn, providing details such as their radius and distance from their primary planet.
Transcribed Image Text:**Educational Content:** **Calculate the Orbital Velocity** Calculate the orbital velocity (in km/s) of a ring particle that orbits \( 1.25 \times 10^5 \) km from the center of Jupiter. **Roche Limit for Jupiter** What is the Roche limit (in km) for Jupiter? **Find the Closest Moon** Find the moon in the table below that is closest to this radius. What is its orbital velocity (in km/s)? --- **Selection of Principal Satellites of the Solar System** | Primary | Satellite | Radius (km) | Distance from Primary (10^3 km) | |---------|-------------|---------------|---------------------------------| | **Jupiter** | Amalthea | 135 × 100 × 78 | 182 | | | Io | 1,820 | 422 | | | Europa | 1,560 | 671 | | | Ganymede | 2,630 | 1,071 | | | Callisto | 2,410 | 1,884 | | | Himalia | ~85 | 11,470 | | **Saturn** | Janus | 110 × 80 × 100| 151.5 | | | Mimas | 196 | 185.5 | | | Enceladus | 260 | 238.0 | | | Tethys | 530 | 294.7 | | | Dione | 560 | 377 | | | Rhea | 765 | 527 | | | Titan | 2,575 | 1,222 | | | Hyperion | 205 × 130 × 110| 1,484 | | | Iapetus | 720 | 3,562 | | | Phoebe | 105 | 12,930 | --- The table lists some principal satellites of Jupiter and Saturn, providing details such as their radius and distance from their primary planet.
**Part 1 of 3**

The circular velocity equation can be used to determine the orbital velocity of a ring particle.

\[ v = \sqrt{\frac{GM}{r}} \]

Calculate the orbital velocity of a ring particle that orbits \( 1.25 \times 10^5 \) km from the center of Jupiter.

\[ v = \sqrt{\frac{GM}{\_\_\_\_\_\_\_}} \, \text{m} \]

\[ v = \_\_\_\_\_\_\_ \, \text{km/s} \]

*Explanation:* 

- The formula \( v = \sqrt{\frac{GM}{r}} \) calculates the orbital velocity (`v`) based on the gravitational constant (`G`), the mass of the central object (`M`), and the radius of the orbit (`r`).
- The problem requires determining the orbital speed for a ring particle at a radius of \( 1.25 \times 10^5 \) km from Jupiter.
- The given details are used to fill in the blanks in the calculation, using the values of `G` and `M` for Jupiter.
Transcribed Image Text:**Part 1 of 3** The circular velocity equation can be used to determine the orbital velocity of a ring particle. \[ v = \sqrt{\frac{GM}{r}} \] Calculate the orbital velocity of a ring particle that orbits \( 1.25 \times 10^5 \) km from the center of Jupiter. \[ v = \sqrt{\frac{GM}{\_\_\_\_\_\_\_}} \, \text{m} \] \[ v = \_\_\_\_\_\_\_ \, \text{km/s} \] *Explanation:* - The formula \( v = \sqrt{\frac{GM}{r}} \) calculates the orbital velocity (`v`) based on the gravitational constant (`G`), the mass of the central object (`M`), and the radius of the orbit (`r`). - The problem requires determining the orbital speed for a ring particle at a radius of \( 1.25 \times 10^5 \) km from Jupiter. - The given details are used to fill in the blanks in the calculation, using the values of `G` and `M` for Jupiter.
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