Part 1 of 3 Find a solution to the system [x'y']=[−62−2−10] [xy][x′y′]=[-62-2-10] [xy] by solving the IVP with initial condition [x(0)y(0)]=[1−4][x(0)y(0)]=[1-4] →x(t)=x→(t)= exp(t) ++ t exp(t)
Part 1 of 3 Find a solution to the system [x'y']=[−62−2−10] [xy][x′y′]=[-62-2-10] [xy] by solving the IVP with initial condition [x(0)y(0)]=[1−4][x(0)y(0)]=[1-4] →x(t)=x→(t)= exp(t) ++ t exp(t)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Part 1 of 3
Find a solution to the system
[x'y']=[−62−2−10] [xy][x′y′]=[-62-2-10] [xy]
by solving the IVP with initial condition [x(0)y(0)]=[1−4][x(0)y(0)]=[1-4]
[x'y']=[−62−2−10] [xy][x′y′]=[-62-2-10] [xy]
by solving the IVP with initial condition [x(0)y(0)]=[1−4][x(0)y(0)]=[1-4]
→x(t)=x→(t)= |
|
exp(t) | ++ |
|
t exp(t) |
![Find a solution to the system
[]=[]
-6 2
-2 -10
J][*]
by solving the IVP with initial condition
x (t)
exp(
=
x (0)
[8]=[4]
y(0)
t)
+
181
t exp](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22e84192-4b16-4dc2-817c-afb771201e2b%2F657948c7-3abc-473a-a2f3-cc8cb3b6937f%2F76630hn_processed.png&w=3840&q=75)
Transcribed Image Text:Find a solution to the system
[]=[]
-6 2
-2 -10
J][*]
by solving the IVP with initial condition
x (t)
exp(
=
x (0)
[8]=[4]
y(0)
t)
+
181
t exp
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