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Part 1 How many moles of base were required to react completely with the acid in this reaction? 2.86 x 10-3 mol Ca(OH)2 Part 2 How many moles of HCI were present in the original 25.00 mL of acid? 5.72 x 10-3 mol HCI

Part 1 How many moles of base were required to react completely with the acid in this reaction? 2.86 x 10-3 mol Ca(OH)2 Part 2 How many moles of HCI were present in the original 25.00 mL of acid? 5.72 x 10-3 mol HCI

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 78QAP: When 85.0 mL of 0.250 M Ba(OH)2 solution is added to 85.00 mL of 0.250 M Al (NO3)3 solution, a white...
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Ca(OH), (ag) + 2HCI(aq) . CaCl, (aq) + H,O(1) An aqueous solution of Ca(OH)2with a concentration of 0.152 Mwas used to titrate 25.00 ml of aqueous HCI. 14.13 mL of the Ca(OH)2was required to reach the endpoint of the titration.
Transcribed Image Text:Ca(OH), (ag) + 2HCI(aq) . CaCl, (aq) + H,O(1) An aqueous solution of Ca(OH)2with a concentration of 0.152 Mwas used to titrate 25.00 ml of aqueous HCI. 14.13 mL of the Ca(OH)2was required to reach the endpoint of the titration.
Part 1 How many moles of base were required to react completely with the acid in this reaction? x 10 3 2.86 mol Ca(OH)2 Part 2 How many moles of HCl were present in the original 25.00 mL of acid? 5.72 x 10 -3 mol HCI
Transcribed Image Text:Part 1 How many moles of base were required to react completely with the acid in this reaction? x 10 3 2.86 mol Ca(OH)2 Part 2 How many moles of HCl were present in the original 25.00 mL of acid? 5.72 x 10 -3 mol HCI
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