Parallel light falls on a single slit of width D at a 28.0° angle to the normal (Figure 1). Describe the diffraction pattern. Check all that apply. The intensity is a maximum at 0 = 0°. The intensity is a maximum at = 28.0°. The intensity is a maximum at 0 = 62.0°. mλ m = ±1, ±2,... The intensity minima are sin 0 = mA, The intensity minima are sin 0 = sin 28.0° - mA,, m = ±1, ±2, ... Submit Previous Answers Request Answer × Incorrect; Try Again; 5 attempts remaining
Parallel light falls on a single slit of width D at a 28.0° angle to the normal (Figure 1). Describe the diffraction pattern. Check all that apply. The intensity is a maximum at 0 = 0°. The intensity is a maximum at = 28.0°. The intensity is a maximum at 0 = 62.0°. mλ m = ±1, ±2,... The intensity minima are sin 0 = mA, The intensity minima are sin 0 = sin 28.0° - mA,, m = ±1, ±2, ... Submit Previous Answers Request Answer × Incorrect; Try Again; 5 attempts remaining
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![Parallel light falls on a single slit of width D at a 28.0°
angle to the normal (Figure 1).
Describe the diffraction pattern.
Check all that apply.
The intensity is a maximum at 0 = 0°.
The intensity is a maximum at 0 = 28.0°.
The intensity is a maximum at 0 = 62.0°.
Figure
1 of 1
T
D
28.0°
The intensity minima are sin
=
ma
D
m =
±1, ±2, ...
The intensity minima are sin
=
sin 28.0°
mλ, m = ±1, ±2, ...
D
Submit
Previous Answers Request Answer
× Incorrect; Try Again; 5 attempts remaining
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Transcribed Image Text:Parallel light falls on a single slit of width D at a 28.0°
angle to the normal (Figure 1).
Describe the diffraction pattern.
Check all that apply.
The intensity is a maximum at 0 = 0°.
The intensity is a maximum at 0 = 28.0°.
The intensity is a maximum at 0 = 62.0°.
Figure
1 of 1
T
D
28.0°
The intensity minima are sin
=
ma
D
m =
±1, ±2, ...
The intensity minima are sin
=
sin 28.0°
mλ, m = ±1, ±2, ...
D
Submit
Previous Answers Request Answer
× Incorrect; Try Again; 5 attempts remaining
Provide Feedback
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