Page 111 Practice Problem 4.7: The weight of the reflector (the earth's gravitational pull) and the force the reflector exerts on the earth form an action-reaction magnitude and direction of each of these forces. Answers: 1960 N up. pair. Determine the
Page 111 Practice Problem 4.7: The weight of the reflector (the earth's gravitational pull) and the force the reflector exerts on the earth form an action-reaction magnitude and direction of each of these forces. Answers: 1960 N up. pair. Determine the
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Page 111 Practice Problem 4.7:** The weight of the reflector (the earth’s gravitational pull) and the force the reflector exerts on the earth form an action-reaction pair. Determine the magnitude and direction of each of these forces. *Answer: 1960 N up.*
![**Example 4.7: Tension in a Massless Chain**
**Context:**
To improve acoustics in an auditorium, a sound reflector is suspended by a chain.
**Objective:**
Calculate the tension in a chain supporting a 200 kg sound reflector in equilibrium.
**Assumptions:**
- The mass of the chain is negligible.
**Setup:**
1. **Weight of the Reflector:** The reflector is in equilibrium, indicating forces acting on it are balanced.
2. **Forces:** There are two main forces:
- Weight (\(w\)) of the reflector, acting downward.
- Tension (\(T\)) in the chain, acting upward.
**Calculations:**
- **Weight Calculation:**
\[
w = mg = (200 \, \text{kg})(9.80 \, \text{m/s}^2) = 1960 \, \text{N}
\]
- **Equilibrium Condition:**
For the reflector to be in equilibrium, the upward tension in the chain (\(T\)) must equal the downward weight (\(w\)):
\[
T = 1960 \, \text{N}
\]
**Conclusion:**
- The tension in the chain is \(1960 \, \text{N}\), which equals the weight of the reflector. This ensures the system is in equilibrium.
This example demonstrates the application of Newton's first law (equilibrium of forces) in solving for tension in a chain. For further exploration, refer to video tutorials that can deepen understanding of dynamics and force analysis in various physical contexts.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F28764828-4d1c-44b8-9544-7d79c8b69e6b%2F29829136-3a55-42cd-ae46-049106a5611a%2F2npk7k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Example 4.7: Tension in a Massless Chain**
**Context:**
To improve acoustics in an auditorium, a sound reflector is suspended by a chain.
**Objective:**
Calculate the tension in a chain supporting a 200 kg sound reflector in equilibrium.
**Assumptions:**
- The mass of the chain is negligible.
**Setup:**
1. **Weight of the Reflector:** The reflector is in equilibrium, indicating forces acting on it are balanced.
2. **Forces:** There are two main forces:
- Weight (\(w\)) of the reflector, acting downward.
- Tension (\(T\)) in the chain, acting upward.
**Calculations:**
- **Weight Calculation:**
\[
w = mg = (200 \, \text{kg})(9.80 \, \text{m/s}^2) = 1960 \, \text{N}
\]
- **Equilibrium Condition:**
For the reflector to be in equilibrium, the upward tension in the chain (\(T\)) must equal the downward weight (\(w\)):
\[
T = 1960 \, \text{N}
\]
**Conclusion:**
- The tension in the chain is \(1960 \, \text{N}\), which equals the weight of the reflector. This ensures the system is in equilibrium.
This example demonstrates the application of Newton's first law (equilibrium of forces) in solving for tension in a chain. For further exploration, refer to video tutorials that can deepen understanding of dynamics and force analysis in various physical contexts.
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