Packages for transporting delicate items (e.g., a laptop or glass) are designed to "absorb" some of the energy of the impact in order to protect their contents. These energy absorbers can get very complicated (e.g., the mechanics of Styrofoam peanuts can be complex), but we can begin to understand how they work by modeling them as a linear elastic spring of constant k that is placed between the contents (an expensive vase) of mass m and the package P. Assume that the vase's mass is 3 kg and that the box is dropped from rest from a height of 1.5 m. Treating the vase as a particle and neglecting all forces except for gravity and the spring force, determine the value of the spring constant k so that the maximum displacement of the vase relative to the box is 0.15 m. Assume that the spring relaxes after the box is dropped and that it does not oscillate.

Packages for transporting delicate items (e.g., a laptop or glass) are designed to "absorb" some of the energy of the impact in order to protect their contents. These energy absorbers can get very complicated (e.g., the mechanics of Styrofoam peanuts can be complex), but we can begin to understand how they work by modeling them as a linear elastic spring of constant k that is placed between the contents (an expensive vase) of mass m and the package P. Assume that the vase's mass is 3 kg and that the box is dropped from rest from a height of 1.5 m. Treating the vase as a particle and neglecting all forces except for gravity and the spring force, determine the value of the spring constant k so that the maximum displacement of the vase relative to the box is 0.15 m. Assume that the spring relaxes after the box is dropped and that it does not oscillate.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q1) Determine the angle 0 so that stress values are equal for both rod and what is this stress value? 4mm diameter 6mm diameter В A 16 kN
7. A mass of gaz has an initial and of 0.11 and 15 C tem beco. nes 90 °C. the final of the gas. réspectiveiy, It is to the law unid be respectively. -It is to a of 3.6 litres to the law A of gas has an and of 1.2 litres and 150 °C 142 Basic engineering thermodynenics From equation 14) 1.0.21 x 358 P 1400 -0.053 7 m/kg 7x 0.053 7 0.145 m The yolume of gas before transfer is 0.145 m PV PV2 Now %3D Vi-P T 1400 333 x 0.145 358 %3D pds () = 0.27 m3 (4) te des The volume of the pressure vessel is 0.27 m'. tro 10. An engine ha The air in th Questions- A quantity of gas has an initial pressure of l140 kN/m² and volume 0.14 m. It is then compressed to a pressure of 700 kN/m? while the temperature remains constant Determine the final volume of the gas. through a (0.028 m 2. A quanûty of gas has an initial volume of 0.06 m and a temperature. of 15 °C. It is expanded to a volume of 0.12 m while the pressure remains constant. Determine the final temperature of the gas. For the D. A mass of gas has…
The pipe assembly is subjected to the 70-N force(Figure 1). Figure 400 mm 300 mm 200 mm 250 mm 40 30
A left hand threaded 14 mm diameter A36 steel bolt is stuck in a metal block. Assume the bolt head is flush with the block surface at A. In order to remove the bolt the 50 Nm torque is applied to the bolt head as shown. The block applies a resisting torque "t" to the stuck threads which is assumed to be uniformly distributed along the 50 mm buried depth. G = 75 GPa a) Explain the difference between right and left hand threaded bolts Determine: b) The magnitude of the uniform resisting torque "t" (including proper units) c) The internal torque as a function of x measured from B (a FBD is required) d) The maximum shear stress in the bolt Ans: 92.8 MPa e) The angle of twist of bolt head A with respect to end B Ans: 0.0044 rad f) The largest torque that can be applied to the bolt head before it twists off (Tyield = 150 MPa) %3D
As information for the mechanic, it is desired to evaluate the variation in shear force along the length of the shaft. Therefore, what is the value of the shear force in the central section of the shaft (125 mm < x < 600 mm)? Options: a) The shear force in the central section of the shaft is 0 kN. B) The shear force in the central section of the shaft is 0.8 kN. c) The shear force in the central section of the shaft is 1.5 kN. d) The shear force in the central section of the shaft is 1.48 kN. e) The shear force in the central section of the shaft is 0.82 kN.
=DF=20.033 N d=12m Find mark done.
For the stress element below, when a = 9, b = 4, and c = 5, the principal stress σ2 , the smallest normal stress, is: ____ MPa. Calculate your answer to 1 decimal place. Input then negative '-' sign, if the answer is negative.
write the dimension (interms of MLT) of rate of shear strain: a. M° L°T -1 b. M' L-1 T-1 O. M1L-1 T2 O d. ML-1 T-1
One shaft is in torsion as shown below. If the magnitude of shear stress at point A is 345.6 MPa, calculate the magnitude of the shear stress at point B on the same cross-section as point A: MPa. Calculate your answer to 1 decimal place. 40 mm 30 mm T
70 40* 1.10 m 2.00 m 1.25 m