Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
PA Torv P:0-819 Lagging V lokv Faom above ciauit, V Voittnge daup in xr (25 40735. ol) E lo1a-5/55 V Pha soa Diege m In Faom af ove Pha suar piagaam, - loLo+ 107-35101.x P5L90 - 1OLO + 1.o17 /55V En 1020+0583+0833) 1o.583+ o 833J = Jo. 616 L45 Excitation voutage ( Er) = 1o.616kr lond angle C8)=4.5 Nuw, Lonl CP)= 3mw (P: sincsi] we knuu, 13)CE)C) 3 (E)(V sincs') sin (A.5) sincs) sincs')= 3Xsin(4.5) 9 sin (S) =02354 . s': sin (o2354) : Is' = 13:614 ]

PA Torv P:0-819 Lagging V lokv Faom above ciauit, V Voittnge daup in xr (25 40735. ol) E lo1a-5/55 V Pha soa Diege m In Faom af ove Pha suar piagaam, - loLo+ 107-35101.x P5L90 - 1OLO + 1.o17 /55V En 1020+0583+0833) 1o.583+ o 833J = Jo. 616 L45 Excitation voutage ( Er) = 1o.616kr lond angle C8)=4.5 Nuw, Lonl CP)= 3mw (P: sincsi] we knuu, 13)CE)C) 3 (E)(V sincs') sin (A.5) sincs) sincs')= 3Xsin(4.5) 9 sin (S) =02354 . s': sin (o2354) : Is' = 13:614 ]

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
Explain what is going on!
: lorv P- 1 Mw Pf: 0-819 daaging E Jメ。 V: lokv Faom above ciranit, 40.7/135.01 A V Vorttage daup in xr (2590(40.7635. 01) = lo17.5/55 Pha soz Diagzm In Faom af ove Pha Sor Diagaam, Eg= +と メL9。 - loLo+ 40.7/-3501 x 25L90 - 1OLO + 1.o17/55 V E = loLo 0583 +0-833) 1o.583+ o 833j 10.616 L4.5k Excitation Voutage ( E) = 1 o.616kr lond angle (S)=4.5 Now, Load cP) = 3mw we knoLu, sincs) 3)(E)Cり sincs') 3(Eり(レリ sin (A.5) -)5)= sincs') sincs')= 3xsin(4.5) sin (5') = 0.2354 . s': sin (o-2354) : Is' 13 614]
Transcribed Image Text:: lorv P- 1 Mw Pf: 0-819 daaging E Jメ。 V: lokv Faom above ciranit, 40.7/135.01 A V Vorttage daup in xr (2590(40.7635. 01) = lo17.5/55 Pha soz Diagzm In Faom af ove Pha Sor Diagaam, Eg= +と メL9。 - loLo+ 40.7/-3501 x 25L90 - 1OLO + 1.o17/55 V E = loLo 0583 +0-833) 1o.583+ o 833j 10.616 L4.5k Excitation Voutage ( E) = 1 o.616kr lond angle (S)=4.5 Now, Load cP) = 3mw we knoLu, sincs) 3)(E)Cり sincs') 3(Eり(レリ sin (A.5) -)5)= sincs') sincs')= 3xsin(4.5) sin (5') = 0.2354 . s': sin (o-2354) : Is' 13 614]
Expert Solution
steps

Step by step

Solved in 6 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Dielectric breakdown
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS