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PA = - (13.6*1000*9.81*0.14) – (1000*9.81*0.2) + (1000*9.81*0.6) + (101.3*1000)+(0.83*1000*9.81*(0.09+0.14)) PA = 88.5Kpa H.W: Two oil tanks are connected to each other through a manometer. If the difference between the mercury levels in the two arms is 32 in, determine the pressure difference between the two tanks. The densities of oil and mercury are 45 lbm/ft³ and 848 lbm/ft³, respectively. Oil Oil 32 in Mercury

PA = - (13.6*1000*9.81*0.14) – (1000*9.81*0.2) + (1000*9.81*0.6) + (101.3*1000)+(0.83*1000*9.81*(0.09+0.14)) PA = 88.5Kpa H.W: Two oil tanks are connected to each other through a manometer. If the difference between the mercury levels in the two arms is 32 in, determine the pressure difference between the two tanks. The densities of oil and mercury are 45 lbm/ft³ and 848 lbm/ft³, respectively. Oil Oil 32 in Mercury

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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PA = - (13.6*1000*9.81*0.14) - (1000*9.81*0.2) + (1000*9.81*0.6) + (101.3*1000)+(0.83*1000*9.81*(0.09+0.14)) PA = 88.5Kpa H.W: Two oil tanks are connected to each other through a manometer. If the difference between the mercury levels in the two arms is 32 in, determine the pressure difference between the two tanks. The densities of oil and mercury are 45 lbm/ft and 848 lbm/ft³, respectively. Oil Oil 10 in 32 in Mercury
Transcribed Image Text:PA = - (13.6*1000*9.81*0.14) - (1000*9.81*0.2) + (1000*9.81*0.6) + (101.3*1000)+(0.83*1000*9.81*(0.09+0.14)) PA = 88.5Kpa H.W: Two oil tanks are connected to each other through a manometer. If the difference between the mercury levels in the two arms is 32 in, determine the pressure difference between the two tanks. The densities of oil and mercury are 45 lbm/ft and 848 lbm/ft³, respectively. Oil Oil 10 in 32 in Mercury
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