P_IDPlP2P3P455P5P6P7P8SIZE1014184041488184Question 1.The main memory condition at time T = 0 and the table mentioning the processes in ready queuealong with its respective size is shown below. The figure shows that the partition size which aredarkened are being used by some processes, hence cannot be used at this time.www20kb 50kb100kb 100kb75kb 50kb 80kb45kb

Explanation of the Memory Allocation Problem:In this problem, we are tasked with allocating…

Answered: P_ID Pl P2 P3 P4 55 P5 P6 P7 P8 SIZE 10…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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A database is to be shared among several concurrent threads. Some of these threads may want only toread the database (readers), whereas others may want to update (that is, to read and write) the database(writers). Design an algorithm in pseudocode to guarantee fairness between processes such that: no datainconsistency will occur, the readers can read simultaneously, all the readers are to read before writers.Explain on your code how you satisfy these constraints.
This is a discrete math problem. Please explain each step in detail, no cursive writing.
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Consider a computer whose RAM has the following memory partition: 4K, 8K, 20K, 2K. At time T, a snapshot of the process queue is taken and is given below. Queue Head Tail Process PO P1 P2 P3 P4 P5 P6 P7 Memory 2K 14K 3K 6K 6K 10K 7K 20K Usage time 4ms 10ms 2ms 8ms 4ms 1ms 8ms 6ms If the processes are allocated using FCFS algorithm with best-fit memory allocation, calculate the time at which P6 finishes its execution. Assume there is no additional time overhead for allocating these processes.
It is a computer science question based on Operating systems Need the answer and explained solution for "PART (b) ONLY"
Consider a disk queue with requests for I/O to blocks on cylinders 47, 38, 121, 191, 87, 11, 92, 10. The C-LOOK scheduling algorithm is used. The head is initially at cylinder number 63, moving towards larger cylinder numbers on its servicing pass. The cylinders are numbered from 0 to 199. The total head movement (in number of cylinders) incurred while servicing these requests is
Given there are six free memory partitions of sizes 100KB, 300KB, 500KB, 550KB, 250KB and 150KB, respectively in that order. These partitions need to be allocated to five processes of sizes 257KB, 310KB, 68KB, 119KB, 23KB in that order. Assume that the search for free partitions starts from the first memory partition. If the NEXT-FIT algorithm is used with DYNAMIC memory allocation approach, list the sizes of free partitions (holes) available after memory allocation to the five given processes.
We define an m-section to be a sequence of code that can be run concurrently by maximum m threads. There are n threads in a process. Each thread executes a thread function doWork() that calls doCriticalWork() in an infinite loop. Function doCriticalWork() requires that at most m threads run it concurrently. The enter() and leave() functions are used to limit the number of threads within the m- section to a maximum of m and are the only functions that deal with synchronization. The pseudo-code algorithm for the thread function is this: void doWork(...) { while (true) { enter(...); I/ limit access to m threads Il execute m-section doCriticalWork(.); Il run by max. m threads leave(.); I/ leave m-section Il do more work Function enter() returns immediately only if there are less than m threads in the m-section. Otherwise, the calling thread will be blocked. A thread calls leave() to indicate it has finished the m-section. If there was another thread blocked (in enter() waiting to enter the…
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Write a C program Producer – Consumer as a classical problem of synchronizationStep 2. Write a program* that solves the producer - consumer problem. You may use the following pseudo code for implementation.*program to write: produce -consumer problem to produce and consume the alphabet.//Shared data: semaphore full, empty, mutex;//pool of n buffers, each can hold one item//mutex provides mutual exclusion to the buffer pool//empty and full count the number of empty and full buffers//Initially: full = 0, empty = n, mutex = 1//Producer thread do {…produce next item…wait(empty); wait(mutex);…add the item to buffer…signal(mutex); signal(full);} while (1);//Consumer thread do {wait(full) wait(mutex);…remove next item from buffer…signal(mutex); signal(empty);…consume the item } while (1);

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