P8-6 (4th edition) The elementary irreversible organic liquid-phase reaction A + B → C is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volumetric flow rate is 2 dm³/s and CAO = 0.1 kmol/m³. Additional information: HA (273 K) = -20 kcal/mol Hg(273 K) = -15 kcal/mol HO (273 K) = -41 kcal/mol (a) Calculate the PFR and CSTR volumes necessary to achieve 85% conversion. What are the reasons for the differences? CpA = Cpg = 15 cal/(mol. K) = 30 cal/(mol.K) Cpc k = 0.01 L/(mol. s) at 300 K E = 10,000 cal/mol

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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P8-6 (4th edition) The elementary irreversible organic liquid-phase reaction A + B → C is carried
out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the
volumetric flow rate is 2 dm³/s and CAO = 0.1 kmol/m³.
Additional information:
HA (273 K) =
= -20 kcal/mol
Hg (273 K) = -15 kcal/mol
HO(273 K) = -41 kcal/mol
(a) Calculate the PFR and CSTR volumes necessary to achieve 85% conversion. What are the reasons for the
differences?
CpA= Cpg = 15 cal/(mol. K)
= 30 cal/(mol. K)
Cpc
k = 0.01 L/(mol.s) at 300 K
E = 10,000 cal/mol
Note: You can use 'Simpson's rule" if numerical
integration is needed:
X3
[ f(x) dx =
Xo
3h
-Ifo +3f1 +3f2 + f3]
8
h =
X3 - Xo
3
Transcribed Image Text:P8-6 (4th edition) The elementary irreversible organic liquid-phase reaction A + B → C is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volumetric flow rate is 2 dm³/s and CAO = 0.1 kmol/m³. Additional information: HA (273 K) = = -20 kcal/mol Hg (273 K) = -15 kcal/mol HO(273 K) = -41 kcal/mol (a) Calculate the PFR and CSTR volumes necessary to achieve 85% conversion. What are the reasons for the differences? CpA= Cpg = 15 cal/(mol. K) = 30 cal/(mol. K) Cpc k = 0.01 L/(mol.s) at 300 K E = 10,000 cal/mol Note: You can use 'Simpson's rule" if numerical integration is needed: X3 [ f(x) dx = Xo 3h -Ifo +3f1 +3f2 + f3] 8 h = X3 - Xo 3
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