P20.10 E = 29,000 ksi and I = 350 in*. 290 k-ft 1 25 ft- 30 k Problem 20.10 - 13 ft
P20.10 E = 29,000 ksi and I = 350 in*. 290 k-ft 1 25 ft- 30 k Problem 20.10 - 13 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The matrix approach needs to be used to solve for the joint displacements, reactions, and member end forces. Perform calculations in units of k and in. I sincerely need help on how to figure this out.
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