P(19) = Correct Answer: P (19) = = Step 5 of 12 19(0.70) ¹ (1 -0.70) -(0.70)¹9 19! (-19)! 23C19 (0.70)¹0 (1-0.70)23-19 Return to Question 23! 19! (23—19)! (0.70)¹⁹ (0.30)4 (0.70)¹⁹ (0.30)* Show Me Check 19
P(19) = Correct Answer: P (19) = = Step 5 of 12 19(0.70) ¹ (1 -0.70) -(0.70)¹9 19! (-19)! 23C19 (0.70)¹0 (1-0.70)23-19 Return to Question 23! 19! (23—19)! (0.70)¹⁹ (0.30)4 (0.70)¹⁹ (0.30)* Show Me Check 19
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
ChapterA: Appendix A Binomial Expansions
Section: Chapter Questions
Problem 31PE: How would you explain binomial expansions to an elementary algebra student.
Related questions
Question
How do I this calculation? I don't understand how they go to the next step and to solve this problem. How did they get (.30)^4 from ? Please help solve this problem.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
Intermediate Algebra
Algebra
ISBN:
9781285195728
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
College Algebra
Algebra
ISBN:
9781305115545
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
Intermediate Algebra
Algebra
ISBN:
9781285195728
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
College Algebra
Algebra
ISBN:
9781305115545
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning