P1.30 Rigid bar ABC shown in Figure Pl.30 is supported by a pin at bracket A and by tie rod (1). Tie rod (1) has a diameter of 5 mm, and it is supported by double-shear pin connections at Band D. The pin at bracket A is a single-shear connection. All pins are 7 mm in diameter. Assume a 600 mm, b 300 mm, h 450 mm, P = 900 N, and 0-55°. Determine the following: (a) the normal stress in rod (1) (b) the shear stress in pin B (c) the shear stress in pin A (1) %3D Please explain how this angle FIGURE PI.30 became 36.87 Solution Equilibrium: Using the FBD shown, calculate the reaction forces that act on rigid bar ABC. EM, = F, sin(36.87°)X600 mm) 36.87 -(900 N)sin (55°)(900 mm) = 0 E -1 843 092 N
P1.30 Rigid bar ABC shown in Figure Pl.30 is supported by a pin at bracket A and by tie rod (1). Tie rod (1) has a diameter of 5 mm, and it is supported by double-shear pin connections at Band D. The pin at bracket A is a single-shear connection. All pins are 7 mm in diameter. Assume a 600 mm, b 300 mm, h 450 mm, P = 900 N, and 0-55°. Determine the following: (a) the normal stress in rod (1) (b) the shear stress in pin B (c) the shear stress in pin A (1) %3D Please explain how this angle FIGURE PI.30 became 36.87 Solution Equilibrium: Using the FBD shown, calculate the reaction forces that act on rigid bar ABC. EM, = F, sin(36.87°)X600 mm) 36.87 -(900 N)sin (55°)(900 mm) = 0 E -1 843 092 N
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Please clarify how this angle became 36.87 that you referred to
![P1.30 Rigid bar ABC shown in Figure Pl.30 is
supported by a pin at bracket A and by tie rod (1).
Tie rod (1) has a diameter of 5 mm, and it is
supported by double-shear pin connections at Band
D. The pin at bracket Ais a single-shear
connection. All pins are 7 mm in diameter.
Assume a = 600 mm, b 300 mm, h 450 mm, P
= 900 N, and 0= 55°. Determine the following:
(a) the normal stress in rod (1)
(b) the shear stress in pin B
(c) the shear stress in pin A
(1)
Please explain how this angle
became 36.87
FIGURE PI.30
Solution
Equilibrium: Using the FBD shown, calculate
the reaction forces that act on rigid bar ABC.
EM, = F, sin(36.87°)X600 mm)
36,87
-(900 N)sin (55°)(900 mm) = 0
. F = 1,843.092 N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8108bf07-f674-4592-8665-6786f1ae9505%2Fc22d29fe-44f4-4869-96fc-5e56524ca676%2F61qo688_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P1.30 Rigid bar ABC shown in Figure Pl.30 is
supported by a pin at bracket A and by tie rod (1).
Tie rod (1) has a diameter of 5 mm, and it is
supported by double-shear pin connections at Band
D. The pin at bracket Ais a single-shear
connection. All pins are 7 mm in diameter.
Assume a = 600 mm, b 300 mm, h 450 mm, P
= 900 N, and 0= 55°. Determine the following:
(a) the normal stress in rod (1)
(b) the shear stress in pin B
(c) the shear stress in pin A
(1)
Please explain how this angle
became 36.87
FIGURE PI.30
Solution
Equilibrium: Using the FBD shown, calculate
the reaction forces that act on rigid bar ABC.
EM, = F, sin(36.87°)X600 mm)
36,87
-(900 N)sin (55°)(900 mm) = 0
. F = 1,843.092 N
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