Oxygen is a product of the decomposition of mercury(II) oxide as shown below. 2 Hg0(s) → 2 Hg(8) + O2(g) You have determined that 0.006926 moles of O2(g) were produced in this reaction. What volume in L of O2 will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C? Remember the gas constant, R, is 0.08206 L·atm/mol·K.
Oxygen is a product of the decomposition of mercury(II) oxide as shown below. 2 Hg0(s) → 2 Hg(8) + O2(g) You have determined that 0.006926 moles of O2(g) were produced in this reaction. What volume in L of O2 will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C? Remember the gas constant, R, is 0.08206 L·atm/mol·K.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![Oxygen is a product of the decomposition of mercury(II) oxide as shown below.
\[ 2 \text{HgO(s)} \rightarrow 2 \text{Hg(}\ell\text{)} + \text{O}_2\text{(g)} \]
You have determined that 0.006926 moles of \(\text{O}_2\text{(g)}\) were produced in this reaction. What volume in L of \(\text{O}_2\) will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C?
Remember the gas constant, \( R \), is 0.08206 L·atm/mol·K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd0c51564-ce63-4ce5-ba67-3d450ed1127c%2F6428b8ae-b003-4c62-8f3e-b21447f6a7b9%2F69810q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Oxygen is a product of the decomposition of mercury(II) oxide as shown below.
\[ 2 \text{HgO(s)} \rightarrow 2 \text{Hg(}\ell\text{)} + \text{O}_2\text{(g)} \]
You have determined that 0.006926 moles of \(\text{O}_2\text{(g)}\) were produced in this reaction. What volume in L of \(\text{O}_2\) will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C?
Remember the gas constant, \( R \), is 0.08206 L·atm/mol·K.
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