Oxygen is a product of the decomposition of mercury(II) oxide as shown below. 2 Hg0(s) → 2 Hg(8) + O2(g) You have determined that 0.006926 moles of O2(g) were produced in this reaction. What volume in L of O2 will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C? Remember the gas constant, R, is 0.08206 L·atm/mol·K.

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Oxygen is a product of the decomposition of mercury(II) oxide as shown below.

\[ 2 \text{HgO(s)} \rightarrow 2 \text{Hg(}\ell\text{)} + \text{O}_2\text{(g)} \]

You have determined that 0.006926 moles of \(\text{O}_2\text{(g)}\) were produced in this reaction. What volume in L of \(\text{O}_2\) will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C?

Remember the gas constant, \( R \), is 0.08206 L·atm/mol·K.
Transcribed Image Text:Oxygen is a product of the decomposition of mercury(II) oxide as shown below. \[ 2 \text{HgO(s)} \rightarrow 2 \text{Hg(}\ell\text{)} + \text{O}_2\text{(g)} \] You have determined that 0.006926 moles of \(\text{O}_2\text{(g)}\) were produced in this reaction. What volume in L of \(\text{O}_2\) will be produced from the decomposition of 3.0 g of HgO assuming a pressure of 1.5 atm and a temperature of 122°C? Remember the gas constant, \( R \), is 0.08206 L·atm/mol·K.
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