A gas is formed in the reaction shown below. The gas laws can help determine the volume of gas produced. Zn(s) + 2 HCl(aq) → ZnCl, + H2(g) You have determined that 2.695 moles of H2(g) were produced in this reaction. At STP, what volume in L of H, will be produced? Remember the gas constant, R, is 0.08206 L·atm/mol·K.
A gas is formed in the reaction shown below. The gas laws can help determine the volume of gas produced. Zn(s) + 2 HCl(aq) → ZnCl, + H2(g) You have determined that 2.695 moles of H2(g) were produced in this reaction. At STP, what volume in L of H, will be produced? Remember the gas constant, R, is 0.08206 L·atm/mol·K.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Title: Calculating Gas Volume at Standard Temperature and Pressure (STP)
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**Chemical Reaction and Gas Production**
In a chemical reaction, gas is produced as a result of the interaction described by the following equation:
\[ \text{Zn(s)} + 2 \text{HCl(aq)} \rightarrow \text{ZnCl}_2 + \text{H}_2(g) \]
**Problem Statement**
You have determined that 2.695 moles of \( \text{H}_2(g) \) were produced in this reaction.
**Question**
At standard temperature and pressure (STP), what volume in liters of \( \text{H}_2 \) will be produced?
**Important Information**
- The gas constant, \( R \), is 0.08206 L·atm/mol·K.
- Standard Temperature and Pressure (STP) is defined as 0°C (273.15 K) and 1 atm pressure.
**Approach to Solution**
To find the volume of hydrogen gas at STP, use the ideal gas law equation:
\[ PV = nRT \]
Where:
- \( P \) is the pressure (1 atm at STP)
- \( V \) is the volume in liters
- \( n \) is the number of moles (2.695 moles)
- \( R \) is the gas constant (0.08206 L·atm/mol·K)
- \( T \) is the temperature in Kelvin (273.15 K at STP)
Rearranging the formula to solve for volume:
\[ V = \frac{nRT}{P} \]
Substituting the known values:
\[ V = \frac{2.695 \times 0.08206 \times 273.15}{1} \]
Calculate this to find the volume of \( \text{H}_2 \) produced.
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Transcribed Image Text:Title: Calculating Gas Volume at Standard Temperature and Pressure (STP)
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**Chemical Reaction and Gas Production**
In a chemical reaction, gas is produced as a result of the interaction described by the following equation:
\[ \text{Zn(s)} + 2 \text{HCl(aq)} \rightarrow \text{ZnCl}_2 + \text{H}_2(g) \]
**Problem Statement**
You have determined that 2.695 moles of \( \text{H}_2(g) \) were produced in this reaction.
**Question**
At standard temperature and pressure (STP), what volume in liters of \( \text{H}_2 \) will be produced?
**Important Information**
- The gas constant, \( R \), is 0.08206 L·atm/mol·K.
- Standard Temperature and Pressure (STP) is defined as 0°C (273.15 K) and 1 atm pressure.
**Approach to Solution**
To find the volume of hydrogen gas at STP, use the ideal gas law equation:
\[ PV = nRT \]
Where:
- \( P \) is the pressure (1 atm at STP)
- \( V \) is the volume in liters
- \( n \) is the number of moles (2.695 moles)
- \( R \) is the gas constant (0.08206 L·atm/mol·K)
- \( T \) is the temperature in Kelvin (273.15 K at STP)
Rearranging the formula to solve for volume:
\[ V = \frac{nRT}{P} \]
Substituting the known values:
\[ V = \frac{2.695 \times 0.08206 \times 273.15}{1} \]
Calculate this to find the volume of \( \text{H}_2 \) produced.
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