The question is in the image. **Reactivity Series and Oxidation Half-Reactions**This educational content focuses on the reactivity series of metals and their corresponding oxidation half-reactions. The metals are organized from high to low chemical activity, facilitating the understanding of their behavior in electrochemical reactions.**Table: Reactivity Series and Oxidation Half-Reactions**- **Lithium (Li)** - Reaction: \( \text{Li(s)} \rightarrow \text{Li}^+(aq) + \text{e}^- \)- **Potassium (K)** - Reaction: \( \text{K(s)} \rightarrow \text{K}^+(aq) + \text{e}^- \)- **Barium (Ba)** - Reaction: \( \text{Ba(s)} \rightarrow \text{Ba}^{2+}(aq) + 2\text{e}^- \)- **Calcium (Ca)** - Reaction: \( \text{Ca(s)} \rightarrow \text{Ca}^{2+}(aq) + 2\text{e}^- \)- **Sodium (Na)** - Reaction: \( \text{Na(s)} \rightarrow \text{Na}^+(aq) + \text{e}^- \)- **Magnesium (Mg)** - Reaction: \( \text{Mg(s)} \rightarrow \text{Mg}^{2+}(aq) + 2\text{e}^- \)- **Aluminum (Al)** - Reaction: \( \text{Al(s)} \rightarrow \text{Al}^{3+}(aq) + 3\text{e}^- \)- **Zinc (Zn)** - Reaction: \( \text{Zn(s)} \rightarrow \text{Zn}^{2+}(aq) + 2\text{e}^- \)- **Iron (Fe)** - Reaction: \( \text{Fe(s)} \rightarrow \text{Fe}^{2+}(aq) + 2\text{e}^- \)- **Nickel (Ni)** - Reaction: \( \text{Ni(s)} \rightarrow \text{Ni}^{2+}(aq) + 2\text{e}^- \)- **Lead (Pb)** - Reaction: \( \text{Pb(s)} \rightarrow \text{

We have to identify the correct reaction among the following given reactions as follows in step 2:

Oxidation Half-Reaction Element high chemical activity lithium Li(s)Li*(aq) +e potassium K(S) K*(aq) + e barium Bals) Ba*(oq) + 2e calcium Cals) Ca+(oq) + 2e sodium Na(s) Na*(oq) + e magnesium Mg(s) Mg*(og) + 2e aluminum Al(s) AP*(og) + 3e zinc Zn(s) Zn*(aq) - 2e iron Fe(s) Fe*(aq) + 2e nickel Ni(s) Ni*(og) + 2e lead Pb(s) Pb*(og) + 2e" copper Cus) Cu*t(aq) + 2e silver Ag(s) Ag (og) + e According to the table, which reaction is correct? mercury Hg(s) Hg (oq) 2e low chemical activity Pb (s) + 2Li (aq) → 2Li (s) + Pb² (aq) because lithium (Li) is a stronger oxidizing agent than lead (Pb) gold Auts) Au*+(aq) + 3e Zn (s) + Cu²+ (aq) → Zn? (aq) + Cu (s) O because copper (Cu) is a stronger oxidizing agent than zinc (Zn) Fe (s) + Mg (aq) → Fe? (aq) + Mg (s) O. because magnesium (Mg) is a stronger oxidizing agent than iron (Fe) Ag (s) + Li (aq) → Ag' (aq) + Li (s) because lithium (Li) is a stronger oxidizing agent than silver (Ag)

Oxidation Half-Reaction Element high chemical activity lithium Li(s)Li(aq) +e potassium K(S) K(aq) + e barium Bals) Ba(oq) + 2e calcium Cals) Ca+(oq) + 2e sodium Na(s) Na(oq) + e magnesium Mg(s) Mg(og) + 2e aluminum Al(s) AP(og) + 3e zinc Zn(s) Zn(aq) - 2e iron Fe(s) Fe(aq) + 2e nickel Ni(s) Ni(og) + 2e lead Pb(s) Pb(og) + 2e" copper Cus) Cut(aq) + 2e silver Ag(s) Ag (og) + e According to the table, which reaction is correct? mercury Hg(s) Hg (oq) 2e low chemical activity Pb (s) + 2Li (aq) → 2Li (s) + Pb² (aq) because lithium (Li) is a stronger oxidizing agent than lead (Pb) gold Auts) Au+(aq) + 3e Zn (s) + Cu²+ (aq) → Zn? (aq) + Cu (s) O because copper (Cu) is a stronger oxidizing agent than zinc (Zn) Fe (s) + Mg (aq) → Fe? (aq) + Mg (s) O. because magnesium (Mg) is a stronger oxidizing agent than iron (Fe) Ag (s) + Li (aq) → Ag' (aq) + Li (s) because lithium (Li) is a stronger oxidizing agent than silver (Ag)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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